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stiks02 [169]
3 years ago
12

Ratios equilvalent to 3:11

Mathematics
2 answers:
kompoz [17]3 years ago
8 0
9 : 22

12 : 45

15 : 55

18 : 77
Snowcat [4.5K]3 years ago
4 0
6:22
9:33
12:44
15:55
18:66
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Need help on number 2
Minchanka [31]
The initial amount is 4800 and 300 is taken out each month..u will first start by saying how many months are they in a year,12 months...
u will take 12 multiplied by 300 in which u will obtain,3600 and the remaining balance will be 4800 -3600=1200.
u will later on say in 12 months his remaining balance will be 1200,and how many months will be there if his balance will be 1500.
12 months =1200
what about 1500 =15months
8 0
3 years ago
What is the value of x?
Temka [501]

Answer:

x = 35°

Step-by-step explanation:

A triangle = 180°

The 95° is outside of the triangle so it must be smaller.

So say it is 85°

85 + 60 = 145

180 - 145 = 35

6 0
3 years ago
Help plz I need the right answer
Nikolay [14]

Answer:

3 1/5 square units

Step-by-step explanation:

4 units * 4/5 shaded

4*4/5 = 16/5

Changing to a mixed number

5 goes into 16 3 times with 1 left over

3*5 = 15   16-15 = 1

3 1/5 square units

4 0
3 years ago
Kevin is making a picture frame. He has a piece of trim that is 3 feet long.
HACTEHA [7]
Kevin can cut 2 14-inch long pieces with 2/3 of a foot left.
8 0
2 years ago
In this exercise, consider a particle moving on a circular path of radius b described by r(t) = b cos(ωt)i + b sin(ωt)j, where ω
Bingel [31]

Answer:

Acceleration of the particle = bw^{2}

Step-by-step explanation:

We are given the position vector of a particle moving in a circle of radius b units.

r(t) = b cos(ωt)i + b sin(ωt)j

Velocity , v =\frac{dr}{dt} = -bω sin(ωt)i + bω cos(ωt)j

The magnitude of velocity, v =\sqrt{v_x^{2} +v_y^{2} }

Squaring both sides,

v^{2} = b^{2} w^{2}(sin^{2}(wt)+cos^{2}(wt))

Since sin^{2}(wt)+cos^{2}(wt)) = 1

v^{2} = b^{2}w^{2}

The acceleration towards the centre is called the centripetal acceleration and is given by

a = \frac{v^{2} }{r}

a = \frac{b^{2}w^{2}}{b}

a = bw^{2}

3 0
3 years ago
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