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Ivanshal [37]
4 years ago
12

A square garden has a diagonal of 34 ft. Colton wants to put a fence around the entire garden.

Mathematics
2 answers:
Molodets [167]4 years ago
5 0
Hello,
let x the side of the square

x²+x²=34²==>x=√578
Perimeter=4*√578≈96(ft)
Cerrena [4.2K]4 years ago
4 0

Answer:

96 feet

Step-by-step explanation:

Given : A square garden has a diagonal of 34 ft. Colton wants to put a fence around the entire garden.

To Find: How much fencing will he need? Round to the nearest foot.

Solution:

Formula of diagonal of square = \sqrt{2}a

Where a is the side of the square.

Since we are given the diagonal length of square garden = 34 ft.

So,  34=\sqrt{2}a

\frac{34}{\sqrt{2}}=a

24.04=a

Thus the side of the square garden is 24.04 ft.

Now we are supposed to find how much fencing is required

So, we are supposed to find the perimeter of square.

Perimeter of square = 4 \times side

                                  = 4 \times 24.04

                                  = 96.16

Thus he need 96.16 ≈ 96 feet fencing .

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answer is 5 this question

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The answer to a "sum and difference" problem is that the larger number is the average of those given: (43 +15)/2 = 29.

The smaller number can be computed any of several ways, but subtracting the difference works: 29 -15 = 14

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The smaller number is 14.

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You can let the numbers be a and b, and let the sum and difference be s and d. Then you have
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This solution is generic. Even if you have to "show work" on such a problem, you can use this known result to check your work.
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4 years ago
How many times does 59 go into 6
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4 0
4 years ago
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A man has n keys on a key ring, one of which opens the door to his apartment. Having celebrated a bit too much one evening, he r
schepotkina [342]

Answer:

The value is   P(3) =  \frac{1}{n}

Step-by-step explanation:

From the question we are told that

   The number of keys is  n

    The number of keys remaining after the first key is chosen is  n-1

    The probability that he gains entrance with the first key he selects is \frac{1}{n}

      Generally the probability that the first key does not open the door is

             p(F_1) = 1 - \frac{1}{n}  =  \frac{n-1}{n}

      Generally the number of keys remaining after the second key is chosen is  

         n-2

      Generally the probability that he gains entrance with the second key he selects is

        \frac{1}{n-1}

       Generally the probability that the second key does not opens the door is

        P(F_2) = 1-   \frac{1}{n-1} = \frac{n-2}{n-1}

   Generally the probability that he gains entrance with the third key he selects is

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Generally the probability that the door opens with the third key

        P(3) =  p(F_1)  * P(F_2)  *  \frac{1}{n-2}

=>       P(3) =  \frac{n-1}{n} *   \frac{n-2}{n-1} * \frac{n-2}{n-1}

=>        P(3) =  \frac{1}{n}

Note :  

      All the outcome of the events are independent

7 0
4 years ago
Try to simplify 72/6+85/6
Reil [10]
72/6+ 85/6
= (72+ 85)/6
= 157/6
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The final answer is 26 1/6~
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3 years ago
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