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Black_prince [1.1K]
3 years ago
15

You are enclosing a rectangular garden with 180 feet of omamental fencing. The area of the garden is 1800 square feet. What are

the dimensions of the garden?
Mathematics
1 answer:
Brut [27]3 years ago
4 0

Answer:

Step-by-step explanation:

Perimeter is

P = 2L + 2W.  We are given the perimeter as 180 feet, so

180 = 2L + 2W.  Solve this for either L or W.  I chose W, no reason...

180 - 2L = 2W so

90 - L = W  Hold that thought.  We'll come back to it in a minute.

Area is

A = LW.  We are given the area as 1800 square feet, so

1800 = LW.  Sub in 90 - L for W:

1800 = L(90 - L).  Distribute to get a quadratic:

1800=90L-L^2

Get everything on one side and solve for the length by factoring:

-L^2+90L-1800=0

Factor this however you like to factor quadratics, to get the length of

L = 30 and L = 60.  First off, the length is longer than the width in general, so if we want to solve for the width, plug in 60 as L in the equation in bold print:

90 - 60 = W and

30 = W

So L = 60 and W = 30

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Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2
9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2

\implies \left|0.3-\dfrac{3}{5}k\right|=1.6

<u>Solution 1</u>

\implies 0.3-\dfrac{3}{5}k=1.6

\implies -\dfrac{3}{5}k=1.3

\implies k=-\dfrac{13}{6}

<u>Solution 2</u>

\implies -(0.3-\dfrac{3}{5}k)=1.6

\implies -0.3+\dfrac{3}{5}k=1.6

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\implies k=\dfrac{19}{6}

<h3><u>Option 2</u></h3>

\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2

\implies \left|0.3-\dfrac{3}{5k}\right|=1.6

<u>Solution 1</u>

\implies 0.3-\dfrac{3}{5k}=1.6

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6 0
1 year ago
The experimental factor that is manipulated; the variable whose effect is being studied is called ____________
lorasvet [3.4K]

Answer:

The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>

Step-by-step explanation:

Consider the provided information.

In an experiment, the two principal variables are the independent and dependent variable.

An independent variable is the variable that is altered or controlled to test the effects on the dependent variable in a scientific experiment.

The variable which is tested and measured in a scientific experiment is a dependent variable.

From the above definition: The experimental factor that changed or controlled in a scientific experiment is called independent variable.

Therefore, the complete statement is: The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>

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2 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
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Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

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