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2 years ago

Suppose c and d vary inversely, and d = 2 when c = 17.

Mathematics

1 answer:

stepladder [879]2 years ago

4 0

Answer:

if d=2 and c=17

then c=68 and d=8

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Citrus2011 [14]

Answer:

Step-by-step explanation:

I think it is C

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2 years ago

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I don't know how to solve this 2/4 + 3/8=?

algol [13]

Answer:

7/8

Step-by-step explanation:

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2 years ago

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A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

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2 years ago

10 ounces is what fraction of a pound?

kicyunya [14]

There are 16 oz. in a pound.
10/16
5/8

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2 years ago

SomeOne Do This Thank You If u had because if u answered my question u get.................................................... i

jonny [76]

Answer:

Step-by-step explanation:

By gradient, if you mean the "slope" of the linear function, then you have to find two points of the graph and use the "rise over run strategy". Given two coordinates, (x1, y1) and (x2, y2) of a linear function in the form y=mx+b, the slope of the line is (y2-y1)/(x2-x1). This shows the amount of "rise", or the vertical change, and the amount of "run", which is the horizontal change. Rise/Run gives the steepness of the line. The slope can also be modeled by Δy/Δx, which is the change in y over the change in x

Plugging in the given points (0,5) and (-5,0):

(y2-y1)/(x2-x1)= (5-0)/(0-(-5)) = 5/5 = 1

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2 years ago