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Shkiper50 [21]
3 years ago
12

Suppose c and d vary inversely, and d = 2 when c = 17.

Mathematics
1 answer:
stepladder [879]3 years ago
4 0

Answer:

if d=2 and c=17

then c=68 and d=8

please mark me as brainlist ....

hope e will help you

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A goat is tied to one corner of a rectangular shed in a large field full of grass. The rope is 3 yards long and a plan view ( fr
sertanlavr [38]

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3 0
3 years ago
Researchers study the relationship between interpersonal violence and health in college age women. The selected an alpha of 0.05
Elena-2011 [213]

Answer:

There exists a relationship between interpersonal violence and health.

Step-by-step explanation:

The relationship between interpersonal violence and health :

The null hypothesis will be ; the is no relationship between interpersonal violence and health while the alternative will negate the Null ;

If no relationship exists, correlation Coefficient = 0 and if a relationship exists, then correlation Coefficient is not = 0

H0 : ρ = 0

H1 : ρ ≠ 0

α = 0.05

Reported Pvalue = 0.016

Decison region :

Reject H0 ; If Pvalue < α

Therefore, Since Pvalue < α ; we reject H0 and conclude that there exists a relationship between interpersonal violence and health.

8 0
3 years ago
What will be the lowest common denominator for the fractions 2/3 and 4/5?
dusya [7]
To find the lowest common denominator between the fractions, what you need to do is simply write out the multiples of both 3 and 5 and find what multiple is common between both:

3,6,9,12,15
5,10,15

The multiple that is common and is the lowest in both would be 15.

The solution thus is B.15, it is the LCD for the fractions of 2/3 and 4/5.
4 0
3 years ago
Which inequality best models the situation if variable t is the temperature in degrees Celsius?
Julli [10]
Your answer is A because t=temperature and since the temperature is below -18.5 it would be a negative and your equation would be t< -18.5
7 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{1}{3}" alt="\frac{1}{3}" align="a
sweet [91]

\boxed{\dfrac{a}{b}\div\dfrac{c}{d}=\dfrac{a}{b}\cdot\dfrac{d}{c}}\\\\\dfrac{1}{3}\div\dfrac{5}{6}=\dfrac{1}{3}\cdot\dfrac{6}{5}=\dfrac{1\cdot6}{3\cdot5}=\dfrac{6}{15}=\dfrac{6:3}{15:3}=\dfrac{2}{5}

8 0
3 years ago
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