All categories

3 years ago

F(x) = -2x + 9 What is f(2h) ?

Mathematics

2 answers:

Sonbull [250]3 years ago

6 0

Answer:

-4h + 9

Step-by-step explanation:

f(x) = -2x + 9

f(2h) = -2(2h) + 9

f(2h) = -4h + 9

Semmy [17]3 years ago

3 0

Answer:

f(2h) = -4h + 9

Step-by-step explanation:

Jacob: Start with the given function f(x) = -2x + 9 and replace 'x' with 2h:

f(x) = -2x + 9 becomes:

f(2h) = -2(2h) + 9, or

f(2h) = -4h + 9

You might be interested in

A rectangle has a length of 14 yards less than 9 times its width. If the area of the rectangle is 6183 square yards, find the le

Jlenok [28]

Answer:

$l=238\ yards$

Step-by-step explanation:

From the question we are told that:

Area of Rectangle A=6183

Equation of Length

$l=9w-14$

Where

$w=width\ of\ triangle$

Generally the equation for Area of Rectangle is mathematically given by

$A=(9w-14)w$

$A=9w^2-14w$

$6183=9w^2-14w$

$9w^2-14w-6183=0$

$w=28$

Therefore

$l=9(28)-14$

$l=238\ yards$

4 0

3 years ago

Exercise - 4<br>1 Express the following angles into sexagesimal second<br>a. 20° 20

liubo4ka [24]

Answer:

202000''

Step-by-step explanation:

(20*100*100)+(20*100)

200000+2000

202000

5 0

3 years ago

5 and 4 sevenths times negative 2 and 2 fifths

Dimas [21]

Answer:

3/2

Step-by-step explanation:

ugygv

6 0

3 years ago

Determine the answer to 3 + (-5) and explain the steps using a number line

Andreas93 [3]

Answer:

-2

Step-by-step explanation:

3 - 5 = -2

Place the dot on -2 on the number line that is on your problem as the answer. To show the steps on the number line, use your jumps to go back. For example, your starting point will be on 3, and then use your jumps to go back by 5; that means you go into the negatives. For this case, it is -2.

4 0

3 years ago

Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-

Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

$\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0

3 years ago