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dimaraw [331]
3 years ago
6

what do you think would happen to a person if mortor neuron from the grey matter of spinal cord is removed?​

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

Step-by-step explanation:

Introduction

Until World War II, a serious spinal cord injury (SCI) usually meant certain death. Anyone who survived such injury relied on a wheelchair for mobility in a world with few accommodations and faced an ongoing struggle to survive secondary complications such as breathing problems, blood clots, kidney failure, and pressure sores. By the middle of the twentieth century, new antibiotics and novel approaches to preventing and treating bed sores and urinary tract infections revolutionized care after spinal cord injury. This greatly expanded life expectancy and required new strategies to maintain the health of people living with chronic paralysis. New standards of care for treating spinal cord injuries were established: reposition the spine, fix the bones in place to prevent further damage, and rehabilitate disabilities with exercise.

Today, improved emergency care for people with spinal cord injuries, antibiotics to treat infections, and aggressive rehabilitation can minimize damage to the nervous system and restore function to varying degrees. Advances in research are giving doctors and people living with SCI hope that spinal cord injuries will eventually be repairable. With new surgical techniques and developments in spinal nerve regeneration, cell replacement, neuroprotection, and neurorehabilitation, the future for spinal cord injury survivors looks brighter than ever.

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Need help ASAP PLEASE DUE SOON!!!
beks73 [17]

Answer:

11

Step-by-step explanation:

all u need to do is to cube root 1331, because it is a cube. hope i helped.

7 0
3 years ago
Center (2,8) radius 3
velikii [3]
I’m not sure what this question is asking, but I’ll write an equation of this circle you are describing. Here, the x coordinate of the center is h, the y coordinate is k, and radius is r in the equation : (x-h)^2+(y-k)^2=r^2, meaning the equation in this situation is the following: (x-2)^2+(y-8)^2=9
6 0
4 years ago
To show me similarity to this statement, how can it be done?
Alenkasestr [34]

We start with the expression at the left of the equation.

We can combine the terms as:

\begin{gathered} \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}} \\ \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})} \end{gathered}

We can now apply the distributive property for the both the numerator and denominator. We can see also that the denominator is the expansion of the difference of squares:

\begin{gathered} \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2})^2-(\sqrt[]{2-\sqrt[]{3}}))^2} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})+(\sqrt[]{3}-2)\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{2^{}-(2-\sqrt[]{3})^{}} \\ \frac{\sqrt[]{2}\cdot(2+\sqrt[]{3})-\sqrt[]{2-\sqrt[]{3}}\cdot(2+\sqrt[]{3})+\sqrt[]{2}\cdot(\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}\cdot(\sqrt[]{3}-2)}{2-2+\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2+\sqrt[]{3}+\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}(-2-\sqrt[]{3}+\sqrt[]{3}-2)}{\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2\sqrt[]{3})+\sqrt[]{2-\sqrt[]{3}}(-4)}{\sqrt[]{3}} \\ 2\sqrt[]{2}-4\frac{\sqrt[]{2-\sqrt[]{3}}}{\sqrt[]{3}} \end{gathered}

We then can continue rearranging this as:

7 0
1 year ago
If secx = -2, then in which quadrants do the solutions lie?
RUDIKE [14]

ANSWER

2nd and 3rd quadrant.

EXPLANATION

The given trigonometric equation is:

\sec(x)  =  - 2

The secant ratio is negative in the second and third quadrant.

But it is positive in the first and fourth quadrants.

The given secant ratio is negative.

This implies that , the solution to given equation lies in the second and third quadrant.

6 0
3 years ago
Select the correct answer. what is the probability that a person who is older than 35 years has a hemoglobin level between 9 and
Kobotan [32]

Based on the number of people who are older than 35 years and the people with a hemoglobin level between 9 and 11, the probability is 0.531.

<h3>What is the probability of having the required hemoglobin level?</h3>

This question does not have the relevant data attached so I will use a similar question.

The probability that a person is older than 35 and has a hemoglobin level of between 9 and 11 can be found as:

= Person who has hemoglobin level of between 9 and 11 and is above 35 years / Total number of people older than 35 years

= (162 - 40 - 76) / 162

= 0.531

Find out more on probability at brainly.com/question/251701.

#SPJ4

7 0
2 years ago
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