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Alekssandra [29.7K]
3 years ago
8

If point R is on segment ST, then segment RS is the same as segment ST rue or false

Mathematics
1 answer:
jonny [76]3 years ago
6 0
Look it up its simple
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Write the expression in the simplest terms (x^2-10)+(10^2+2)
Leto [7]
X^2+92 is the simplest form first solve the second parentheses. 10^2+2=102 then add -10. 102+-10 is the same as 102-10=92 plug back in x^2+92.
6 0
3 years ago
What are the square roots of 1?
Marta_Voda [28]

Answer:

1

Step-by-step explanation:

1^2=1

3 0
2 years ago
Read 2 more answers
Two trains are traveling towards each other at a constant speed. The trains are currently 714 miles from each other. The speeds
shutvik [7]
55mph.

you can solve it using the equation distance=speed x time

your total distance is 714, and you have 2 trains, one traveling some speed, x, and one traveling x+8, both traveling for 7 hours. 
your equation would look like this
714 = x(7) + (x+8)(7)
and you can then solve for x, which would be 47. this is the speed of the slower train, but 47+8=55 with give you the speed of the faster train. 
6 0
3 years ago
Show that KEYS is a square if K (-2, 4) ,E (4,2 ), Y(2,-4 ) ,S (-4, -2) are the co- ordinates of the vertices.
Lyrx [107]

Answer:

KEYS is a square

Showing as plotted and connected points

See the attached

4 0
3 years ago
The graphs below are both absolute value functions. The equation of the redgraph is f(x) = |xl. Which of these is the equation o
grigory [225]

ANSWER

\Rightarrow y=\frac{1}{2}|x|

EXPLANATION

We want to find the absolute value function for the line in blue.

The general form of an absolute value function is:

y=a|x-h|+k

where (h, k) = vertex

From the line, the vertex of the graph in blue is:

(0,0)

To find a, we have to pick a point (x, y) on the line and input it into the general function.

Let us pick (2, 1).

Therefore, we have:

\begin{gathered} 1=a|2-0|+0 \\ 1=a|2|=2a \\ \Rightarrow a=\frac{1}{2} \end{gathered}

Therefore, the absolute value function is:

\begin{gathered} y=\frac{1}{2}|x-0|+0 \\ \Rightarrow y=\frac{1}{2}|x| \end{gathered}

3 0
1 year ago
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