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dimaraw [331]
3 years ago
11

2(2t+4)=3-4(24-8t)bruh help​

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0

Answer:

\frac{101}{28}=t

Step-by-step explanation:

2(2t+4)=3-4(24-8t)\\4t+8=3-96+32t\\8-3+96=32t-4t\\101=28t\\\frac{101}{28}=t

STatiana [176]3 years ago
3 0

Answer:

3.607 to the nearest thousandth.

Step-by-step explanation:

2(2t+4)=3-4(24-8t)

Solving for t:

4t + 8 = 3 -  96 + 32t

8 - 3 + 96 = 32t - 4t

101 = 28t

t = 101/28

= 3.607 .

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Answer:

c. 10 cm

Step-by-step explanation:

The parallel sides of trapizium are the bases so

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the perpendicular distance means the height so lets find the height

area of trapizium= <u>B1 + B2</u> × h

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2

{105cm}^{2}(the \: given \: area)  =  \frac{9cm(the \: given \: base) + 12cm(the \: given \: base)}{2}  \times h

{105cm}^{2}  =  \frac{21cm}{2}  \times h

now we crisscross

{105cm}^{2} \times 2 = 21cm \times h

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\frac{ {210cm}^{2} }{21cm}  =  \frac{21cm \: }{21cm}  \times h

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hope u like it ‍❤️‍‍❤️‍‍❤️‍

For any question comment me

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3 years ago
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A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

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