calculeaza lungimea segmentului ab in fiecare dintre cazuri:A(1,5);B(4,5);A(2,-5),B(2,7);A(3,1)B(-1,4);A(-2,-5)B(3,7);A(5,4);B(-
Tatiana [17]
Answer:
1. 3; 2. 12; 3. 5; 4. 13; 5. 10; 6. 10
Step-by-step explanation:
We can use the distance formula to calculate the lengths of the line segments.
1. A (1,5), B (4,5) (red)
2. A (2,-5), B (2,7) (blue)
3. A (3,1), B (-1,4 ) (green)
4. A (-2,-5), B (3,7) (orange)
5. A (5,4), B (-3,-2) (purple)
6. A (1,-8), B (-5,0) (black)
Answer:
Two or more independent functions (say f(x) and g(x)) can be combined to generate a new function (say g(x)) using any of the following approach.
h(x) = f(x) + g(x)h(x)=f(x)+g(x) h(x) = f(x) - g(x)h(x)=f(x)−g(x)
h(x) = \frac{f(x)}{g(x)}h(x)=
g(x)
f(x)
h(x) = f(g(x))h(x)=f(g(x))
And many more.
The approach or formula to use depends on the question.
In this case, the combined function is:
f(x) = 75+ 10xf(x)=75+10x
The savings function is given as
s(x) = 85s(x)=85
The allowance function is given as:
a(x) = 10(x - 1)a(x)=10(x−1)
The new function that combined his savings and his allowances is calculated as:
f(x) = s(x) + a(x)f(x)=s(x)+a(x)
Substitute values for s(x) and a(x)
f(x) = 85 + 10(x - 1)f(x)=85+10(x−1)
Open bracket
f(x) = 85 + 10x - 10f(x)=85+10x−10
Collect like terms
mark as brainiest
f(x) = 85 - 10+ 10xf(x)=85−10+10x
f(x) = 75+ 10xf(x)=75+10x
Answer: the number of item A that you sold is 11
the number of item B that you sold is 2
Step-by-step explanation:
Let x represent the number of item A that you sold.
Let y represent the number of item B that you sold.
The total number of item A and item B sold is 13. This means that
x + y = 13
The cost of item A is $8 and the
cost of item B is $4. The total amount if money made is $88. This means that
8x + 4y = 88 - - - - - - - - - -1
Substituting x = 13 - y into equation 1, it becomes
8(13 - y) + 4y = 88
104 - 8y = 88
8y = 104 - 88 = 16
y = 16/8 = 2
x = 13 - y = 13 - 2 = 11
Answer: The only graph that shows a proportional relationship is the line that crosses the origin point (0,0).
Explanation
The other graphs are linear functions but not not proportional relationships.
The general form of a proportional relationship is y = kx, where k is the proportionality constant. So, for x = 0 you will always obtain y = 0.
The general form of a linear relationshio is y = kx + b, being b the y-intercept, so if the y-intercept is not 0, it is not a proportional relationship. That is what happens with the other three graphs.
