For the answer to the question above, Tim practices his backhand and his serve at least 2 hours each day this means X =< 2 ( less than or equal to 2 hrs). He works less on his backhand than his serve and practices his serve more than an hour daily. <span>Y < 1</span>
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as

n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) =
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
13.9 or 14
Step-by-step explanation:
a^2 + b^2 = c^2
5^2 + 13^2 = c^2
25 + 169 = 197
square root 197 to get c
c = 13.9 (14 rounded up)
Helpful thing to note is that the hyptoenuse will always be longer than your "long side" of the triangle
1) cscΘ = - 2
=>
1
------ = - 2
sinΘ
=> sinΘ = - 0.5 => Θ is in the third and fourth quadrant
=> Θ = 180° + 30° = 210°
and Θ = 360° + 30° = 330°
2) tan Θ = √3
=> Θ = 60° and Θ = 180° + 60° = 240°
Idk this answer because no triangles are shaded.