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AleksAgata [21]
3 years ago
10

The system of linear equations -2y+ y = 8 and -3x -y=7 is graphed below. What is the solution to the system of equations?

Mathematics
2 answers:
faltersainse [42]3 years ago
8 0

Answer:

x=1/3       y= -8

step explanation:

-2y+y=   8 then -y=8          y= -8

-3x-(-8) =7

-3x +8 =7

-3x=-1

x=1/3          y= -8

victus00 [196]3 years ago
5 0

Answer:

x= 1/3

y = -8

Step-by-step explanation:

-2y+ y = 8 equation 1

-3x -y =7 equation 2

using equation 1 we have:

-2y+ y = 8

-y = 8

y = -8 equation 3

using equation 3 in equation 2 we have:

-3x -y=7  

-3x -(-8)=7  

-3x +8 =7

-3x = 7-8

-3x = -1

x= 1/3

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lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

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3 years ago
Which plane is parallel to plane LMQ?
GrogVix [38]

Answer:

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X + y = 3 <br>-2x + 4y = 6
Finger [1]
I'm assuming this is a system of equations you want solved so,

x = -y + 3

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Factoring using GCF 15cd + 30c^2d^2
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Answer:

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Step-by-step explanation:

greatest common factor is 15cd

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8 0
2 years ago
Determine the type(s) of the triangle with the given coordinates. X(6,1) Y(-2,-3) Z(0,3)
jeyben [28]

The triangle with the given coordinates X(6,1) Y(-2,-3) Z(0,3) is an isosceles triangle.

The given coordinates are X(6,1) Y(-2,-3) Z(0,3).

<h3>What are coordinates?</h3>

A coordinate system is a system in geometry that employs one or more integers, or coordinates, to define the position of points or other geometric components on a manifold, such as Euclidean space, in a unique way.

We know that, Distance formula =\sqrt{(x_{2}-x_{1}  )^{2}+(y_{2}-y_{1}  )^{2}  }

Now, XY=\sqrt{(-2-6)^{2}+(-3-1)^{2}  }=\sqrt{80} units

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XZ=\sqrt{(0-6)^{2}+(3-1)^{2}  }=\sqrt{40} units

Here, YZ=XZ

Hence, the triangle with the given coordinates X(6,1) Y(-2,-3) Z(0,3) is an isosceles triangle.

To know more about the coordinate geometry visit:

brainly.com/question/20393391

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