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Neko [114]
3 years ago
11

How do you do this question?

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

Step-by-step explanation:

∫ 15 sin(√(at)) dt

Use substitution:

If x = √(at), then:

dx = ½ (at)^-½ (a dt)

dx = a / (2√(at)) dt

dx = a/(2x) dt

dt = (2/a) x dx

Plugging in:

∫ 15 sin x (2/a) x dx

30/a ∫ x sin x dx

Integrate by parts:

If u = x, then du = dx.

If dv = sin x dx, then v = -cos x.

∫ u dv = uv − ∫ v du

= 30/a (-x cos x − ∫ -cos x dx)

= 30/a (-x cos x + ∫ cos x dx)

= 30/a (-x cos x + sin x + C)

Substitute back:

30/a (-√(at) cos(√(at)) + sin(√(at)) + C)

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

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Substitute <br><br> -3x-8y=4<br> -2x+7y=15
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the fraction might not be in lowest terms.
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3 years ago
PLEASE HELP ASAP 25 PTS TO RIGHT/BEST ANSWER
Novay_Z [31]
Subtract 1111 from both sides

5{e}^{{4}^{x}}=22-115e​4​x​​​​=22−11


 

Simplify 22-1122−11 to 1111

5{e}^{{4}^{x}}=115e​4​x​​​​=11



 

Divide both sides by 55

{e}^{{4}^{x}}=\frac{11}{5}e​4​x​​​​=​5​​11​​



 

Use Definition of Natural Logarithm: {e}^{y}=xe​y​​=x if and only if \ln{x}=ylnx=y

{4}^{x}=\ln{\frac{11}{5}}4​x​​=ln​5​​11​​



 

: {b}^{a}=xb​a​​=x if and only if log_b(x)=alog​b​​(x)=a

x=\log_{4}{\ln{\frac{11}{5}}}x=log​4​​ln​5​​11​​



 

Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}log​b​​x=​log​a​​b​​log​a​​x​​

x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=​log4​​logln​5​​11​​​​



 

Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}log​b​​x​c​​=clog​b​​x
\log{4}log4 -> \log{{2}^{2}}log2​2​​ -> 2\log{2}2log2

x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=​2log2​


Answer= −0.171
7 0
3 years ago
Given the below sequence:-1, -3, -5, -7, . . .
vekshin1

Answer:

A. The next 3 terms are —9, —11, —13

B. The sequence is Arithmetic

C. The sequence has a common difference of —2

Common difference = T2 — T1 or = T3 — T2

=T2 — T1 = —3 —(—1) = —2 or

= T3 — T2 = —5 —(—3) = —2

D. Tn = a + d(n—1)

a = first term = —1

d = Common difference = —2

n = 27

T27 = —1 + —2(27—1)

T27 = —1 + —2(26)

T27 = —1 —52

T27 = —53

3 0
3 years ago
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