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2 years ago

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A jar contains five blue marbles and three red marbles. Suppose you choose a marble at random, and do not replace it. Then you

choose a second marble. Find the probability of the following event. Both of the selected marbles are red.

1 answer:

VladimirAG [237]2 years ago

6 0

For the first event
P=3/(5+3)=3/8=0.375

Total became 2 red and 5 blue .... 7 total

For the second event
P=2/(5+2)=2/7= 0.2857

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Dr. Oguz counted the number of cubs in 10 tiger cub litters and then arranged the numbers from smallest to largest. The numbers

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The mean absolute deviation (MAD) is 1.2

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2 years ago

The volume of a rectangular pyramid is 900 cubic centimeters.It has a length of 10 centimeters and a width of 9 centimeters. Wha

MariettaO [177]

The height of a rectangular pyramid is 30 cm.

volume of rectangular pyramid = (length x width x height) / 3

Given:
Volume = 900 cm³
Length = 10 cm
Width = 9 cm
Height = ?

V = lwh/3
900 cm³ = (10cm * 9cm * h)/3
900 cm³ * 3 = (90cm² * h)/3 * 3
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to check:
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2 years ago

f of x equals 4 x over quantity x squared minus 16. Show all work to identify the asymptotes and zero of the function.

yuradex [85]

Given:

The function is

$f(x)=\dfrac{4x}{x^2-16}$

To find:

The asymptotes and zero of the function.

Solution:

We have,

$f(x)=\dfrac{4x}{x^2-16}$

For zeroes, f(x)=0.

$\dfrac{4x}{x^2-16}=0$

$4x=0$

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Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

$x^2-16=0$

$x^2=16$

Taking square root on both sides, we get

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2 years ago

A random sample of 38 wheel chair users were asked whether they preferred cushion type A or B, and 28 of them preferred type A w

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Answer:

The statement that cushion A is twice as popular as cushion B cannot be verified

Step-by-step explanation:

From the question we are told that:

Sample size n=38

Type a size A $X_a=28$

Type a size B $X_b=10$

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$P(a)=\frac{28}{38}$

$P(a)=0.73$

Generally the equation for A to be twice as popular as B is mathematically given by

$P(b)+2P(b)=3P$

Therefore Hypothesis

$Null H_0: p \leq \frac{2P}{3P} \\Altenative H_A:p>\frac{2P}{3P}$

Generally the equation normal approx of p value is mathematically given by

$z=\frac{x-np_0-0.5}{\sqrt{np_0(1-p_0)} }$

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Therefore from distribution table

$Pvalue=1-\theta (0.75)$

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Therefore there is no sufficient evidence to disagree with the Null hypothesis $H_0$

Therefore the statement that cushion A is twice as popular as cushion B cannot be verified

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Answer is C

Hope that helped ^^

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3 years ago

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