Answer:
a) x = 80.40
s = 29.54
b) lower limit = 69.53
upper limit = 91.27
Step-by-step explanation:
The mean price is:
The standard deviation is
![s=\sqrt{\frac{1}{n-1}\sum(x_i-\bar X)^2}=\sqrt{\frac{1}{19}[(50-80.4)^2+...+(70-80.4)^2]} \\\\s=\sqrt{\frac{15,471}{19} }=\sqrt{814.25} =29.54](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%28x_i-%5Cbar%20X%29%5E2%7D%3D%5Csqrt%7B%5Cfrac%7B1%7D%7B19%7D%5B%2850-80.4%29%5E2%2B...%2B%2870-80.4%29%5E2%5D%7D%20%5C%5C%5C%5Cs%3D%5Csqrt%7B%5Cfrac%7B15%2C471%7D%7B19%7D%20%7D%3D%5Csqrt%7B814.25%7D%20%3D29.54)
We have to calculate a 90% CI for the mean.
The z-value for a 90% confidence interval is z=1.645.
The margin of error is:
The 90% CI is
Answer:
2/18
Step-by-step explanation:
Answer:
The percentage of error in the question is 75%.
Step-by-step explanation:
To find the percentage of error, we need to subtract the actual value from the value that was expected, divide the result by the expected value.
He predicted that the crop would produce 8 bushels so this is our expected value. The actual value, which is the number of bushels produced, is 14.
- If we make the calculation (14 - 8) / 8 = 6 / 8.
- And then multiply the result by 100 to find the percentage, (6 / 8) x 100 = 75.
So the percentage of error in the question is 75%.
I hope this answer helps.
