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Softa [21]
4 years ago
5

Scores on a dental anxiety scale range from 0​ (no anxiety) to 20​ (extreme anxiety). The scores are normally distributed with a

mean of 11 and a standard deviation of 4. Find the​ z-score for the given score on this dental anxiety scale.
Mathematics
1 answer:
solniwko [45]4 years ago
6 0

Answer:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Step-by-step explanation:

The following information is missing in the question:

We have to find z-score for the given score on this dental anxiety scale: 12, 6

We are given the following information in the question:

Mean, μ = 11

Standard Deviation, σ = 4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

where x is the given score on this dental anxiety scale.

For x = 12

z_{score} = \displaystyle\frac{12-11}{4} = 0.25

For x = 6

z_{score} = \displaystyle\frac{6-11}{4} = -1.25

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Make an approximate conversion from English to metric. <br><br> 9 ft to meters
Anna71 [15]

Answer:

2.7 meters

Step-by-step explanation:

I hope this helped

4 0
3 years ago
The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?
AleksAgata [21]

Answer:

\large \boxed{2}

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}

Check:

\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}

It checks.

7 0
3 years ago
A filling machine puts an average of four ounces of coffee in jars, with a standard deviation of 0.25 ounces. forty jars filled
Lunna [17]
Let's attack this problem using the z-score concept.  The sample std. dev. here is (0.25 oz)/sqrt(40), or 0.040.  Thus, the z score representing 3.9 oz. is
        3.9 - 4.0
z = -------------- = -2.5
          0.040 

In one way or another we must find the area under the std. normal curve that lies to the left of z = -2.5.  Use a table of z-scores or a calculator with built-in statistics functions.  According to my TI-83 Plus calculator, that area is

0.006.  One way of interpreting this that with so small a standard deviation, most volumes of coffee put into the jars are very close to the mean, 4 oz.
4 0
4 years ago
Help, I don’t understand this DeltaMath question
djyliett [7]
I can use the angle and the length of JH to find the length of IJ.

To do this, I look at the relationship IJ and JH have to the 52 degree angle. JH is opposite to angle I, and IJ is adjacent to angle I. Because the two side lengths are opposite and adjacent, I use the tangent function to solve this.

Tangent of an angle = the length of the opposite side / the length of the adjacent side. This is just another way to say tan(x)=opposite/adjacent

Now I can fill in what I know...
tan(52)=4.2/x
Now, I want to isolate x.
tan(52) = 4.2/x
x(tan(52))=4.2
x=4.2/tan(52)

Now I put 4.2/tan(52) into a calculator and get x = 3.3 ft

Hope this helps!
7 0
3 years ago
Y&gt;= -5x + 8 what is m?​
Sonbull [250]

Answer:

The slope = -5

Step-by-step explanation:

y ≥ -5x + 8

Look at the problem as y = -5x + 8 and compare to the slope intercept form. The slope = -5

6 0
3 years ago
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