Question

Scores on a dental anxiety scale range from 0​ (no anxiety) to 20​ (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the​ z-score for the given score on this dental anxiety scale.

Answer 1

Answer:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Step-by-step explanation:

The following information is missing in the question:

We have to find z-score for the given score on this dental anxiety scale: 12, 6

We are given the following information in the question:

Mean, μ = 11

Standard Deviation, σ = 4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

where x is the given score on this dental anxiety scale.

For x = 12

$z_{score} = \displaystyle\frac{12-11}{4} = 0.25$

For x = 6

$z_{score} = \displaystyle\frac{6-11}{4} = -1.25$