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Elden [556K]
2 years ago
14

90 POINTS PLEASE HELP Describe the three main trigonometry functions, their ratios and reciprocal functions.

Mathematics
1 answer:
snow_lady [41]2 years ago
7 0

Answer and Step-by-step explanation:

There are three reciprocal trigonometric functions

making a total of six including cosine, sine, and tangent.

→The reciprocal cosine function is secant: sec(Ф)=1/cos(Ф).

→The reciprocal sine function is cosecant, csc(Ф)=1/sin(Ф).

→The reciprocal tangent function is cotangent, expressed two ways: cot(Ф)=1/tan(Ф) or cot(Ф)=cos(Ф)/sin(Ф).

We've already learned the basic trig ratios:

sin(A) = a/c

cos(B) = b/c

tan(C) = a/b

   

But there are three more ratios to think about:

→Instead of  a/c, we can consider c/a  

​→Instead of  b/c, we can consider c/b  

→Instead of  a/b, we can consider b/a  

These new ratios are the reciprocal trigonometric ratios, and we’re about to learn their names.

<u>The cosecant (csc)</u>

The <u>cosecant</u> is the reciprocal of the sine. It is the ratio of the hypotenuse to the side opposite a given angle in a right triangle.

sin(A) = opp / hyp  = a/c

csc(A) = hyp / opp = c/a

<u>The secant (sec)</u>

The <u>secant </u>is the reciprocal of the cosine. It is the ratio of the hypotenuse to the side adjacent to a given angle in a right triangle.

cos(A) = adj/hyp = b/c

sec(A) = hyp/adj = c/b  

<u>The cotangent (cot)</u>

The <u>cotangent </u>is the reciprocal of the tangent. It is the ratio of the adjacent side to the opposite side in a right triangle.

tan(A) = opp/adj = a/b

cot(A) =adj/opp = b/c

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d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

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f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

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c. P(B/A)= P(AnB)/P(A)

             =0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

7 0
2 years ago
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