Given the table below which contains data from 200 endothemic reactions involving <span>sodium bicarbonate:
![\begin{tabular} {|c|c|} Final Temperature Conditions&Number of Reactions\\[1ex] 266 K&48\\ 271 K&60\\ 274 K&92 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AFinal%20Temperature%20Conditions%26Number%20of%20Reactions%5C%5C%5B1ex%5D%0A266%20K%2648%5C%5C%0A271%20K%2660%5C%5C%0A274%20K%2692%0A%5Cend%7Btabular%7D)
We find the probability distribution function as follows:
Let X denote the final temperature, then
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I hope this picture helps, but next time try to chose a number to cancel out the fraction. Example, y=1/3x+4 chose 3,6,9 and other multiples of 3.
Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
Answer: 17
21-4=17
4+17=21
21+17=38 and so on..
