Call n, the first of those consecutive terms, then three consecutive terms are:n, n +1, and n +2.
So, the equation will be n + (n +1) + (n +2) = 467
=> n + n + 1 + n + 2 = 467
=> 3n + 3 = 467
All of them are valid forms of the equation for the sum of three consecutive integers is 467.
You can solve it now, if you want:
3n = 467 - 3
3n = 464
n = 464 / 3
n = 154.6
The solution means that there are not three consecutive numbers whose sume is 467.
You can verifiy that if you take 154 + 155 + 156 = 465
And 155 + 156 + 157 = 468
Rearrange to: x^2 + 18x - 25 = 0
Then factorise (I like to do it by completing the square):
(x + 9)^2 -81 -25 = 0
(x + 9)^2 = 106
x + 9 = sqrt(106)
The sol'ns are:
x = -9 + and - sqrt(106)
Answer:
the answer is probably inverse or joint or combined,really haven't seen this type of variation before
Step-by-step explanation:
HOPE IT HELPS YA
