<h2>
Answer: (x = 1)</h2>
Step-by-step explanation:
We are given the equation <em>6(5x - 3) = 1/3(24x + 12)</em>, and we must find the value of <em>x</em>.
The first step is to distribute. Distribute the <em>6 </em>to <em>5x </em>and <em>-3</em>, and distribute<em> 1/3 </em>to <em>24x </em>and <em>12</em>. This give us the equation <em>30x - 18 = 8x + 4</em> to work with.
The next step is to get <em>x </em>by itself. In order to do this, subtract 18 from each side of the equation. This gives get's rid of the <em>-18</em> and get's <em>x </em>by itself on one side of the equation and gives us the equation <em>30x = 8x +22</em>.
Now that x is by itself on one side of the equation, get 22 by itself on the other side of the equation. The way to do this is to subtract 8x from each side. This gives us the equation <em>22x = 22</em>.
Divide both sides by 22 and get the equation <em>x = 1</em>
<em>Hope that this helps and clears it up! Have a great day!</em>
Answer:
no it is not
Step-by-step explanation:
it would be 54
Two over four because you just multiply by two2/4
One milion is 1000 thousand or 1,000,000
so million:one is 1,000,000:1
Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is
where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A
We do the same for company C
This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A
