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3 years ago

I REALLY NEED HELP ON THIS

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

7 0

Answer:

question 4. Is A.

Step-by-step explanation:

kvasek [131]3 years ago

4 0

Answer:

for question 4 it A.

Step-by-step explanation:

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Pls help answer these four questions 50 points + brainlyest

Pie

1. None are correct it would be either 1/3, 2/6, 3/9, 4/12, 5/15
2.B
3.C
4.C

6 0

2 years ago

Read 2 more answers

Emerson is making a punch that contains 60% grape juice and the rest lemon-lime soda. The punch has 2 liters of lemon-lime soda.

valina [46]

Part A.

Consider a punch containing L liters.

60% of these that is $\frac{60}{100}L=0.6L$ is grape juice, and the rest, 0.4 L is lemon-soda.

so, for the variable L, the total amount of punch, the total amount of grape juice is 0.6 L
and the amount of lemon soda in the punch is 0.4L

Part B.

For L=2, we substitute and get:

0.6 L=0.6 * 2 liters = 1.2 liters of grape juice

0.4 L = 0.4 * 2 liters = 0.8 liters of lemon soda.

5 0

3 years ago

Will an object with a density of. 97 g/ml float or sink in water explain

Ainat [17]

I would say the object will float because the density of water is 999.99kg/m which is slightly less than 1g but still more than the object.

3 0

3 years ago

In a right angle,the altitude to a 6ft hypotenuse.Find the length of the altitude and each leg.

Nuetrik [128]

Answer:a=3.6 and b=4.8

Step-by-step explanation:(a^2)+(b^2)=(c^2)

Where c is hypotenuse is equal to 6. A right triangle is also known as a 3,4,5 triangle where the 2 legs are 3 and 4 and hypotenuse is 5. Find the factor in size difference by dividing your hypotenuse of 6 by the hypotenuse of 5 you get 1.2. Now multiply the 3 and 4 by 1 2 to get your answers of 3.6 and 4.8.

To check work simply plug in your legs as a and b

(3.6^2)+(4.8^2)=(6^2)

(12.96)+(23.04)=(36)

6 0

3 years ago

Simplify

Diano4ka-milaya [45]

Answer:

$\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}$

Step-by-step explanation:

$16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}$

$=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}$

5 0

3 years ago