3 years ago

How do you solve 8/11(n-10)=64

Mathematics

1 answer:

krek1111 [17]3 years ago

6 0

Answer:

n = 98

Step-by-step explanation:

8/11 x (n - 10) = 64

multiply both sides of the equation by 11/8

11/8 x 8/11 x (n-10) = 11/8 x 64

reduce the numbers with greatest common divisor 11

1/8 x 8 (n-10) = 11/8 x 64

n - 10 = 11 x 8

multiply the numbers

n - 10 = 88

so then you add the numbers

n = 88 + 10

n= 98

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