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3 years ago

11

HELP ASAP!! PLEASE EXPLAIN! THIS IS Creating Equations and Inequalities of One-Variable

2 answers:

lakkis [162]3 years ago

7 0

Explained --------A one-variable equation is an equation that has exactly one variable in it. Similarly, a one-variable inequality is an inequality that has exactly one variable in it. Setting up one-variable equations and inequalities is an extremely useful tool in mathematics.

Evgen [1.6K]3 years ago

6 0

Answer:

The steps to doing this are as follows:

1. Identify the unknown and represent it with a variable.

2. Set up an equation or inequality using that variable.

3. Solve the equation or inequality to find an answer to the problem.

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Maksim231197 [3]

You'd do $0.50 × 11 = $5.50 which is the total cost for the rides, and then you'd add $6 to make $11.50 which is the total amount you spent.

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yuradex [85]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

What is 4 divided by 631

vagabundo [1.1K]

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3 years ago

Consider a rectangle that is inscribed with its base on the x-axis and its upper corners on the parabola y=C−x2, with C>0. Wh

olya-2409 [2.1K]

Answer:

\frac{4(9c-4)}{27

Step-by-step explanation:

Assuming c positive, we find that this parabola is open down with vertex on the y axis above the origin.

If a rectangle is formed, then it would have two vertices on either side of the y axis of the parabola with remaining two vertices on x axis.

Due to symmetry let us take vertices on x axis as (a,0) and (-a,0)

Corresponding vertices on the parabola would be

$(b, c-a^2) and (b,c-a^2)$

Now the rectangle has width = 2b and

length = $c-a^2$

So area of the rectangle =

$A(a) =2a(c-a^2)\\A(a) = 2ac-a^3$

Use derivative test to find a which gives maximum area

$A'(a) = 2a-3a^2\\A"(a) = 2-6a$

Equate I derivative to 0 to get

a =0 or a = 2/3

a cannot be 0

A" is negative for a = 2/3

So maximum when a =2/3

and maximum area

= $2(\frac{2}{3} )(c-\frac{4}{9})\\ =\frac{4(9c-4)}{27}$

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3 years ago