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3 years ago

How do I cancel a 7 day free trial before I get charge

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

6 0

Answer: You Divide it by 2

Step-by-step explanation: and add 8

densk [106]3 years ago

6 0

I think sometimes it won’t charge you but idk

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Which series of transformations would transform triangle A into similar triangle A' in Quadrant IV? A. Rotate triangle A 90 cloc

VikaD [51]

Answer:

<u>option D</u>

Step-by-step explanation:

It is required to transform triangle A into similar triangle A' in Quadrant IV.

The given triangle in Quadrant II.

We will check the options:

A. Rotate triangle A 90 clockwise about the origin then translate five units up.

Wrong because triangle A' will be at Quadrant I.

B. Dilate triangle A by a scale factor of 4. Translate triangle A to the left.

Wrong because triangle A' will be at Quadrant II.

C. Reflect triangle A across the y-axis and then translate the triangle 3 units up and 2 units to the right.

Wrong because triangle A' will be at Quadrant I.

D. Reflect triangle A across the x-axis and then reflect the triangle across the y-axis.

True Because reflection triangle A across the x-axis, the first image will be at Quadrant III, then reflection the first image across the y-axis, we will get triangle A' will be at Quadrant IV.

<u>So, the answer is option D</u>

6 0

3 years ago

on Saturday afternoon, six friends agreed to call each other. each friend talked to every other friend once. how many phone call

jonny [76]

I think I might be right but you do 6x6 which would be 36.

5 0

4 years ago

In a fraternity with 40 members , 18 take mathematics, 5 take both mathematics and physics, and 8 take neither mathematics nor p

garri49 [273]

Answer: 14 members take physics but not mathematics

Step-by-step explanation:

Please see the attached for a diagrammatic representation of this situation.

Since there are 40 members but 8 did not offer any of mathematics or physics, then:-

40 - 8 = 32

So, 32 members of the fraternity offer maths, physics or both.

5 members offer both mathematics and physics .

Since 5 members offer both mathematics and physics, the number of members that offer maths alone = 18 - 5

Let us use "P" to represent the number of members that offer physics. Therefore, the number of members that offer only physics = (P - 5)

Now, if we add up the members that offered maths only, the members that offered both mathematics and physics and the members that offered only physics, it will be equal to the 32 members that offered at least a subject.

Therefore, (18 - 5) + 5 + (P - 5) = 32

18 - 5 + 5 + P - 5 = 32

18 + P - 5 = 32

P + 13 = 32

P = 32 - 13

P = 19

19 members offered physics out of the 32 members that offered maths, physics or both.

To find out the number of people or members that offered physics only, we subtract the number of members that offered the two subjects (5) from a total of 19 members that offered Physics

19 - 5 = 14

Therefore, 14 members of the fraternity offer only physics

5 0

3 years ago

Read 2 more answers

I WILL MAKE YOU THE BRAINLIEST

3241004551 [841]

Answer:

4 3/4 & 19/4

Step-by-step explanation:

Note that for the point, the whole number to the left is 4, and the whole number to the right is 5. This means that the number is 4 (& some).

Next, note that there are 2 lines in between the numbers This means that the amount in between is by 1/4s.

This means that the denominator would have to be a 4 (which means only C & D work).

Now, note that both says 4 3/4, and so change it to an improper fraction

4 = 16/4

16/4 + 3/4 = 19/4

D) is your answer choice.

5 0

3 years ago

Read 2 more answers

Sam and Jeremy have ages that are consecutive odd integers. The product of their ages is 783, which equation could be used to fi

stepladder [879]

(2x+1)=Jeremy´s age
(2x+3)=Sam´s age.
we suggest this equation:
(2x+1)(2x+3)=783
4x²+6x+2x+3=783
4x²+8x-780=0
x²+2x-195=0

We solve this quadratic equation:
x=[-2⁺₋√(4-4*1*(-195))]/2=(-2⁺₋28)/2

x₁=(-2-28)/2=-15 this solution is not valid.
x₂=(-2+28)/2=13

Jeremy´s age=2x+1=2*13+1=27
Sam´s age=2x+3=2*13+3=29

7 0

3 years ago