Answer: Not really sure what you mean by algebra tiles but I do know that x=2.
Answer:
B
Step-by-step explanation:
Multiply through by x+5
2(x + 1) = x + 5 - 1 Combine like terms
2x + 2 = x + 4 Subtract 2 from both sides.
2x = x + 4 - 2
2x = x + 2 Subtract x from both sides.
2x - x = 2 Combine
x = 2
B
Let the total toys be x.
The first has (1/10)x = x/10
The third child has one more toys than the first = x/10 + 1
The fourth has double of the third: = 2* (x/10 + 1) = 2x/10 + 2
Since we know that the second child has 12 more toys than the first
Therefore the Second minus First = 12.
First let us find the second.
1st + 2nd + 3rd + 4th = x
x/10 + 2nd + (x/10 + 1) + (2x/10 + 2) = x
2nd + x/10 + x/10 + 1 + 2x/10 + 2 = x
2nd + x/10 + x/10 + 2x/10 + 1 + 2 = x
2nd + 4x/10 + 3 = x
2nd = x - 4x/10 - 3
2nd = 6x/10 - 3
But recall
2nd - 1st = 12
6x/10 - 3 - x/10 = 12
6x/10 - x/10 = 12 + 3
5x/10 = 15
5x = 15 * 10
x = 15*10 /5
x = 30
So there were 30 toys in all.
Answer:
b = y-intercept; The equation is y = mx + b. The x and y variables remain as letters, but m and b are replaced by numbers (ex: y = 2x + 4, slope = 2 and y-intercept = 4). The following video will show a few examples of understanding how to use the slope and intercept from an equation.
Vertex (4, -13) y = x^2 - 8x + 3 x-coordinate of vertex: x = -b/(2a) = 8/2 = 4 y-coordinate of vertex: y(4) = 16 - 32 + 3 = -13 Vertex (4, -13) To find y-intercepts, make x = 0 --> y = 3 To find x-intercepts, solve the quadratic equation y = 0 Use the improved quadratic formula D = d^2 = b^2 - 4ac = 64 - 12 = 52 --> d = +- 2sqrt13 There are 2 x-intercepts (2 real roots): x = -b/(2a) +- d/(2a) = 8/2 +- (2sqrt13)/2 = 4 +- sqrt13 graph{x^2 - 8x + 3 [-40, 40, -20, 20]}
Step-by-step explanation:
