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Elan Coil [88]
3 years ago
6

What is the Inverse Equationf(x) =6x-1 ?? please I need help!​

Mathematics
1 answer:
Scrat [10]3 years ago
5 0

Answer:

f^{-1}(x)=\frac{x+1}{6}

Step-by-step explanation:

So we have the function:

f(x)=6x-1

To find the inverse function, switch x and f(x), change f(x) to f⁻¹(x), and solve for f⁻¹(x). Therefore:

f(x)=6x-1

Switch:

x=6f^{-1}(x)-1

Add 1 to both sides:

x+1=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{x+1}{6}

And that's our answer :)

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Helpppppp and explain tooo thank you :)
Wittaler [7]

Answer:

{5, 6, 7}

Step-by-step explanation:

When we have a given relation, the domain is the set of inputs, and the range as the set of the outputs.

so for a function f(x), and a domain {a. b. c}

The range is:

{f(a), f(b), f(c)}

In this case, we have:

f(x) = x + 6

and the domain is {-1, 0, 1}

Then the range is:

{ f(-1), f(0), f(1) }

{-1 + 6, 0 + 6, 1 + 6}

{5, 6, 7}

The correct option is the third one.

4 0
3 years ago
Michael has finished 25% of an art project that has taken
Amanda [17]

Answer:

16 hours

Step-by-step explanation:

\frac{25}{100} = \frac{4}{x}

  • cross multiply

25x = 400

  • divide

x = 16

6 0
3 years ago
Graph the system of linear equations -1/2y=1/2x+5 and y=2x+2
raketka [301]
I agree with the other answer however the first equation would need to be
Y=-1X-10
7 0
3 years ago
A rock is thrown into the air. The height of the rock is modeled by s(t) = −16tଶ + 64t + 80 feet for t ≥ 0 seconds. The rock hit
ExtremeBDS [4]

Answer:

144 feets

Step-by-step explanation:

Look on s(t) like quadratic function. We need to find maximum of the function using 1st diferetioal:

s(t)=-16t^2+64t+80

s’(t)=-32t+64

S’(t)=0 if t=2

For t>2, s’(t)<0

For t<2, s’(t)>0. So the maximum od function is in the point 2.

S(2)=-16*4+64*2+80=-64+128+80=144

6 0
3 years ago
A jar contains 0.65 liter of lime juice and 0.40 liter of orange juice. Meg poured 0.35 liter of cranberry juice into the jar. S
Natali5045456 [20]
(0.65+0.4+0.35)-0.10 is equal to 1.3 

combining like terms is how you solve this problem 
6 0
3 years ago
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