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Svetllana [295]
3 years ago
9

Given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form.

Mathematics
1 answer:
Schach [20]3 years ago
4 0

Answer:

A. x-2y=-12

Step-by-step explanation:

We have been given an equation of a line in point-slope form. We are asked to write our given equation in standard form.

y-3=\frac{1}{2}(x+6)

Since we know that standard form of equation is: ax+by=c, where, a, b and c are constants.

Let us multiply both sides of our given equation by 2.

(y-3)*2=2*\frac{1}{2}(x+6)

2y-6=x+6

Let us add 6 to both sides of our equation.

2y-6+6=x+6+6

2y=x+12

Let us subtract x from both sides of our equation.

2y-x=x-x+12

2y-x=12

Multiply both sides of our equation by -1.

-2y+x=-12

Rearranging our equation we will get,

x-2y=-12

Therefore, the standard form of our given equation is x-2y=-12 and option A is the correct choice.

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Determine the quadrant(s) in which (x,y) is located so that the condition is satisfied. (Select all that apply.)
Svetllana [295]
I’m not exactly sure but I think II and IV.
4 0
3 years ago
Find the area of the region that is inside the square and outside the circle. The circle has a diameter of 8 inches. Round to th
raketka [301]

Answer: 13.7 in²

<u>Step-by-step explanation:</u>

Area of Square:

A = s²

  = 8²

  = 64

Area of Circle:

A = π r²

   = π (4)²

   = 16π

   ≈ 50.3

Area of Square - Area of Circle:

           64          -        50.3         = 13.7

5 0
3 years ago
Please help me!!!!!!!!!!!!!​
monitta

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities:    tan (A/2) = (sinA)/(1 + cosA)

                                                                     cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = \frac{\sqrt2}{2}

<u>Proof LHS → RHS</u>

Given:                       cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o

Rewrite Fraction:     cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o

Half-Angle Identity:   \dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}

Substitute:                  \dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}

Simplify:                      \dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}

                               =\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}

                               =\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)

                               =\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}

                               =\dfrac{4}{2}

                               = 2

LHS = RHS:  2 = 2  \checkmark

7 0
4 years ago
Determine the equivalent system for the given system of equations:
Volgvan

Answer:

Step-by-step explanation:

5x+3y=1

4x-5y=4

--------------

4(5x+3y)=4(1)

-5(4x-5y)=-5(4)

----------------------

20x+12y=4

-20x+25y=-20

----------------------

37y=-16

y=-16/37

5x+3(-16/37)=1

5x-48/37=1

5x=1+48/37

5x=37/37+48/37

5x=85/37

x=(85/37)/5

x=(85/37)(1/5)

x=85/185

x=17/37

Answer: x=17/37, y=-16/37. (17/37, -16/37)

-----------------------------

5x+3y=1

8x-10y=4

-----------------

8(5x+3y)=8(1)

-5(8x-10y)=-5(4)

----------------------

40x+24y=8

-40x+50y=-20

----------------------

75y=-12

y=-12/75=-4/25

5x+3(-4/25)=1

5x-12/25=1

5x=1+12/25

5x=25/25+12/25

5x=37/25

x=(37/25)/5

x=(37/25)(1/5)

x=37/125

Answer: x=37/125, y=-4/25. (37/125, -4/25).

-------------------------------

5x+3y=1

9x-2y=5

---------------

2(5x+3y)=2(1)

3(9x-2y)=3(5)

---------------------

10x+6y=2

27x-6y=15

---------------

37x=17

x=17/37

5(17/37)+3y=1

85/37+3y=1

3y=1-85/37

3y=37/37-85/37

3y=-48/37

y=(-48/37)/3

y=(-48/37)(1/3)

y=-48/111

Answer: x=17/37, y=-48/111. (17/37, -48/111).

--------------

6 0
3 years ago
Read 2 more answers
Find the distance between each pair of points. round your answer to the nearest tenth.
goldenfox [79]

Answer:

5.4

Step-by-step explanation:

To find the distance between each pair of points, we use the distance formula, which is:

d = \sqrt{(x_{2}-x_{1})^2 + (y_{2} -y_{1})^2  }

So we have

x_{1} = 2\\ x_{2} = 4\\y_{1} = 8\\y_{2}=3

When we plug in the values into the formula we get:

d = \sqrt{(4-2)^2 + (3-8)^2}

d = \sqrt{4 + 25}\\ =\sqrt{29}\\ =5.4

3 0
3 years ago
Read 2 more answers
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