Given:
y = 2x + 6
x - the number of miles between restaurant and point of delivery
y - the number of minutes between the time an order is place and the time it is delivered.
The correct conclusion is:
<span>C) It takes the restaurant about 6 minutes to prepare each order for delivery
2x is the time it takes to deliver the order, every mile is traveled within 2 minutes.
6 is the number of minutes it takes to prepare the order before it will be set out for delivery.
</span>
Answer:
Option B
Step-by-step explanation:
Looking at the options, option B is correct because when multiplying it by matrix A, it yields the matrix AB as follows;
First row of A multiplied by first column of matrix in option D;
(1 × -1) + (0 × 0) + (0 × 0) = -1 which corresponds to the first number on the first row of Matrix AB
Since majority of matrix AB are zero, I will just prove the ones that are not zero.
Thus;
Second row of matrix A is multiplied by second column of matrix in option D;
(0 × 0) + (-1 × -1) + (0 × 0) = 1 which is same as 2nd number on second row in matrix AB
Lastly, third row of matrix A is multiplied by third column of matrix in option D;
(0 × 0) + (0 × 0) + (1 × -1) = -1 which is same as third number in third row in matrix AB
Answer:
![r = \sqrt[3]{\frac{3V}{4 \pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%20%5Cpi%7D%7D)
Step-by-step explanation:
From the formula of volume of a sphere we have to isolate "r" on one side of the equation i.e. we have to make "r" the subject of the equation.
![V=\frac{4}{3} \pi r^{3}\\\\ \text{Multiplying both sides by 3/4 we get}\\\\\frac{3V}{4} = \pi r^{3}\\\\ \text{Dividing both sides by } \pi \\\\ \frac{3V}{4 \pi} = r^{3}\\\\\text{Takeing cube root of both sides}\\\\\sqrt[3]{\frac{3V}{4 \pi}} = r](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E%7B3%7D%5C%5C%5C%5C%20%5Ctext%7BMultiplying%20both%20sides%20by%203%2F4%20we%20get%7D%5C%5C%5C%5C%5Cfrac%7B3V%7D%7B4%7D%20%3D%20%5Cpi%20r%5E%7B3%7D%5C%5C%5C%5C%20%5Ctext%7BDividing%20both%20sides%20by%20%7D%20%5Cpi%20%5C%5C%5C%5C%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%7D%20%3D%20r%5E%7B3%7D%5C%5C%5C%5C%5Ctext%7BTakeing%20cube%20root%20of%20both%20sides%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%20%5Cpi%7D%7D%20%3D%20r)
Therefore:
