If you will make a Punnett square for this problem it will look like this:
T t
t Tt tt
t Tt tt
So the genotype in the first and third box would be Tt. On the second and fourth box, we have tt.
So your answer would be: C. 1 = Tt; 2 = Tt; 3 =tt; 4 = tt
Answer:
Nah I'm good
Explanation:
I only answered for the free points
Answer:
I think the answer is I and III because there are gaps and 2 values that have a high amount
plus, this is the only logical answer
This might could help
http://diy.stackexchange.com/questions/998/what-are-the-different-gauges-of-electrical-wire-availabl...
