Answer:
3x^2
Step-by-step explanation:
Given:
(3x) * {(1/x)^-4 }* (x^-3)
=(3x) * {1 ÷ (1/x)^4} * {1/x^3}
=(3x) * {1(x/1)^4} * (1/x^3)
=(3x) * (x^4) * (1/x^3)
=(3x) (x^4) (1) / x^3
Multiply the denominators
=3x^5 / x^3
Can also be written as
=3*x*x*x*x*x / x*x*x
Divide the x
= 3*x*x / 1
=3x^2
Answer:
Downloading 28 songs will cost $26.64.
Step-by-step explanation:
Given that a brand-new music service is offering specials on individual song downloads, and the cost is $ 0.74 for each song up to 20 songs per month, and the cost doubles to $ 1.48 per download for any number of downloads over 20, to determine how much would it cost to download 28 songs the following calculation should be performed:
(20 x 0.74) + (8 x 1.48) = X
14.8 + 11.84 = X
26.64 = X
Therefore, downloading 28 songs will cost $ 26.64.
Domain is the x and range is y so your domain is 2,3,4,5 and your range is 0 and 4
If you put four fingers up and add them it makes eight so if you put down all of the eight finger down two at a time and there is no finger left up it’s even
The total required amount CB should have been receiving for
the past 4 hours should be:
Required quantity = (75 mL / hr) * 4 hr
Required quantity = 300 mL
The actual quantity CB received however is only:
Actual quantity = (45 mL / hr) * 4 hr
Actual quantity = 180 mL
Therefore the deficit is:
Deficit quantity = 300 mL – 180 mL
Deficit quantity = 120 mL
Since in a 1 liter (1000 mL) bag there is 40 mEq of KCl,
therefore the needed extra mEq of KCl that CB has to receive now is:
Additional KCl = 120 mL * ( 40 mEq / 1000 mL)
<span>Additional KCl = 4.8 mEq </span>
