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3 years ago

Name the peninsula that separates the bering sea from the sea of okhotsk?

Geography

1 answer:

katovenus [111]3 years ago

6 0

Answer:

Sea of Okhotsk, Russian Okhotskoye More, or Ochotskoje More, northwestern arm of the Pacific Ocean, bounded on the west and north by the east coast of Asia from Cape Lazarev to the mouth of the Penzhina River, on the east and southeast by the Kamchatka Peninsula and the Kuril Islands, on the south by the northern coast of the Japanese island of Hokkaido, and on the southwest by Sakhalin Island. Except for the small area touching Hokkaido, the sea is completely enclosed by Russian territory. Its area covers 611,000 square miles (1,583,000 square km), and it has a mean depth of about 2,818 feet (859 metres). The sea’s maximum depth is 11,063 feet (3,372 metres).

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3 years ago

When Carla solved for the height from the ground to the point where the ladder

Westkost [7]

Answer:

<em>See explanation</em>

Explanation:

Given

Represent the vertical angle with $\theta$

$\theta = 75$

The question has incomplete details because the length of the ladder is not given; neither is the distance between the ladder and the wall given.

<em>See attachment for illustration</em>

So, this solution will be based on assumptions.

Represent

- The height from ground to the top of the ladder with y

- The length of the ladder with L

- The distance between the ladder and the wall with x

Carla could solve for y in any of the following ways:

1. Tan formula

$tan \theta = \frac{opp}{adj}$

In this case:

$tan \theta = \frac{x}{y}$

Multiply both sides by y

$y * tan \theta = \frac{x}{y} * y$

$y * tan \theta = x$

Divide both sides by tan

$y = \frac{x}{tan \theta}$

$y = \frac{x}{tan 75}$

This can be used if the distance (x) between the ladder and the wall is known.

Assume x = 15

$y = \frac{15}{tan 75}$

$y = 4.02$

2. Cosine formula

$cos \theta = \frac{adj}{hyp}$

In this case:

$cos \theta = \frac{y}{L}$

Multiply both sides by L

$L * cos \theta = \frac{y}{L} * L$

$Lcos \theta = y$

$y = Lcos \theta$

$y = Lcos75$

This can be used if the length (L) of the ladder is known.

Assume L = 15

$y = 15 * cos75$

$y = 3.88$

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