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Studentka2010 [4]
3 years ago
11

Derst Inc. sells a particular textbook for $140. Variable expenses are $25 per book. At the current volume of 6,000 books sold p

er year the company is just breaking even. Given these data, the annual fixed expenses associated with the textbook total: A) $400,000 B) $690,000 C) $840,000 D) $150,000
Business
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

Option (B) is correct.

Explanation:

Given that,

Selling price of a product = $140 per textbook

Variable expenses = $25 per book

Books sold per year = 6,000 books (It is the break even point)

The break even point indicates that there is no profit or loss incurred at the sales.

This means that the sales revenue is equal to the total cost incurred to produced these goods.

Sales per unit - Variable cost per unit - Fixed costs per unit = 0

$140 - $25 - Fixed costs = 0

$115 = Fixed costs per unit

Therefore, the total amount of fixed cost is calculated as follows:

= Fixed cost per unit × Number of books sold

= $115 × 6,000

= $690,000

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Golden Marine Stores Company manufactures special metallic materials and decorative fittings for luxury yachts that require high
drek231 [11]

Answer:

A. The company paid a higher cost for the direct materials than allowed by the standards.

Explanation:

The following is a logical explanation for this variance:

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3 years ago
Requirement 3. The company marketing vice president believes a new sales promotion that costs $ 140 comma 000 would increase sal
gregori [183]

Answer:

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Variable manufacturing expense = 240000×20 = 4,800,000

Sales commission expense = 240000×8 =1,920,000

Fixed manufacturing overhead = $2,400,000

Fixed operating expenses = 245,000

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8 0
3 years ago
Automobile repair costs continue to rise with the average cost now at $367 per repair.† Assume that the cost for an automobile r
vovikov84 [41]

Answer:

a)  0.1728

b)  0.09183

c) 0.7354

d) $ 222.25

Explanation:

Given

mean = \mu = $367

Standard deviation = \sigma =$88

Cost of automobile repair is normally distributed.

a) We have to find P( x > 450 )

P( x > 450 ) = 1 - P( x <= 450 )

Using excel function,   P( x <= x ) = NORMDIST (x,  \mu, \sigma, 1 )

P( x > 450 )   = 1 - NORMDIST( 450 , 367, 88, 1 )

= 1 - 0.8272 = 0.1728

P( x > 450 ) = 0.1728

b)  P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( x < 250 ) = 0.09183

c) P( 250 < x < 450 ) = P( x <450 ) - P( x < 250 )

P( x <450 ) = NORMDIST( 450 , 367, 88, 1 ) = 0.8272

P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( 250 < x < 450 ) = 0.8272 - 0.09183 = 0.7354

P( 250 < x < 450 ) = 0.7354

d) We have P( X < a ) = 0.05

We have to find a.

Using Excel, = NORMINV ( Probability, \mu, \sigma )

a = NORMINV ( 0.05 , 367, 88 ) = 222.2529

Cost = $ 222.25

8 0
3 years ago
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