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Mila [183]
1 year ago
8

Find the value of c if a line with slope 3/4 passes through the points (1,8) and (5,c) PLEASE HELP

Mathematics
1 answer:
seropon [69]1 year ago
5 0

The value of c, if a line with a slope of 3/4 that passes through the points (1,8) and (5,c), is 11.

<h3>What is the equation of a line?</h3>

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

Given that the line has a slope of 3/4 and passes through the point (1,8). Therefore, we need to substitute the slope and the coordinates in the equation of the line, to get the value of the y-intercept.

y = mx + c

8 = (3/4)(1) + c

8 = (3/4) + c

c = 8 - (3/4)

c = 29/4

Now, the line also passes through (5,c), therefore, if we substitute the value of slope and y-intercept in the equation,

y = mx + c

c = (3/4)(5) + (29/4)

c = (15/4) + (29/4)

c = 44/4

c = 11

Hence, the value of c, if a line with a slope of 3/4 that passes through the points (1,8) and (5,c), is 11.

Learn more about Equation of Line here:

brainly.com/question/21511618

#SPJ1

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Alina [70]
3.4×10⁻¹⁴ × 1.8×10²⁸

= (3.4 x 1.8) x 10⁽⁻¹⁴⁺²⁸⁾

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Answer is A.

Hope it helps!
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Step-by-step explanation:

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Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

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for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

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for y(x=1) = 0

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1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

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Step-by-step explanation:

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