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erma4kov [3.2K]
3 years ago
5

a rocket is launched from the ground at an initial velocity of 39.2 meters per second. which equation can be used to model the h

eight of the rocket after t seconds?
Mathematics
1 answer:
Sonbull [250]3 years ago
4 0

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{39.2}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{\textit{from the ground, so }0}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-4.9t^2+39.2t+0\implies h(t)=-4.9t^2+39.2t

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WARRIOR [948]

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3 0
3 years ago
Consider the following vectors in component form.
Mrac [35]

Answer:

Cartesian Coordinate System

• Also called

rectangular coordinate

system

• x- and y- axes intersect

at the origin

• Points are labeled (x,y)

Polar Coordinate System

– Origin and reference

line are noted

– Point is distance r from

the origin in the

direction of angle θ,

ccw from reference

line

– Points are labeled (r,θ)

Cartesian to Polar Coordinates

• r is the hypotenuse and θ

an angle

θ must be ccw from

positive x axis for these

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Step-by-step explanation:

7 0
2 years ago
Find the 19th term of the arithmetic sequence whose common difference is =d5 and whose first term is =a12.
emmasim [6.3K]
An=a1+d(n-1)
a1=first term
d=common difference
n=which term

common difference is 5 first term is 2
an=5+2(n-1)
19th term is n=19
a19=5+2(19-1)
a19=5+2(18)
a19=5+36
a19=41

19th term is 41
4 0
3 years ago
If log3 8 ≈1.8928, evaluate log3 72
zysi [14]

Answer:

≈ 3.8928

Step-by-step explanation:

log base 3 of 72 is approximately 3.8928

you would need to plug this into a calculator to solve

3 0
3 years ago
Please help ASAP!!
frutty [35]
The answer is D, 
a(n) = 4/5 + 1/6(n- 1)
just took the test :)
6 0
3 years ago
Read 2 more answers
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