a rocket is launched from the ground at an initial velocity of 39.2 meters per second. which equation can be used to model the h

eight of the rocket after t seconds?

Mathematics

1 answer:

Sonbull [250]3 years ago

4 0

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{39.2}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{\textit{from the ground, so }0}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-4.9t^2+39.2t+0\implies h(t)=-4.9t^2+39.2t$

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4 years ago

Please help on number 9 and 10. Will mark brainliest.

Alenkasestr [34]

Answer:

9. 1.24 mL

10. $5.93

Step-by-step explanation:

<u>Question 9:</u>

If the dosage of medicine is 0.01 mL per pound of weight of the patient, and the patient's weight is 124 pounds, we can set up an equation to solve for how much medicine the patient would need to take:

Dosage of medicine per pound of body weight x Total body weight = Total medicine required

0.01 * w = m,

where w is total body weight and m is total medicine required.

To solve for the dosage the patient needs, just plug the numbers into the right places (124 for w and leave m as it is):

0.01 * 124 = m

1.24 = m

Therefore, a patient with a body weight of 124 pounds would need a 1.24 mL dosage.

<u>Question 10:</u>

To make the multiplication easier, we could rewrite 15% as 0.15 ( because 15% = 15/100):

0.15 * Total bill = Total tax payed for bill (Also can be written as $\frac{15}{100} * 39.51$ )