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3 years ago

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Luis is getting balloons for his father's birthday party. He wants each balloon string to be 12 feet long. At the party store, s

tring is sold by the yard. If Luis wants to get 56 balloons, how many yards of string will he need?

2 answers:

SSSSS [86.1K]3 years ago

7 0

Answer:

<h2>224yd.</h2>

Step-by-step explanation:

According to the problem, we know that each ballon string is 12 feet long. But, Luis need to know this amount in yards, to then calculate how much he needs for the 56 balloons.

So, 1 yard equals 3 feet. Using this relation we can do the math:

$12ft\frac{1yd}{3ft} =4yd$

According to the proportion, 12 feet equals 4 yards. So, each ballon string is 4 yards long. But, Luis needs 56 of them, we just have to multiply to know the total: $56ballons(4yd) = 224yd$

Therefore, Luis needs 224 yards of string for the 56 balloons.

zubka84 [21]3 years ago

5 0

Answer:

he will need 224 yards of string

Step-by-step explanation:

56 ballons *12 feet=672 feet

each yard is 3 feet so he will need

1yard--->3feet

X<-------672feet=224 yards

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3 years ago

Read 2 more answers

An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s

maks197457 [2]

Answer:

$W_s \approx5.3$

Step-by-step explanation:

From the question we are told that

Height $H=3.5ft$

Weight $W= 6ft$

Depth $D=0.95ft$

Generally the equation for ellipses is given as

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

Where

$b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\$

$\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1$

Generally to find y in the equation $\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

$y=-b+d$

$y=-1.75+0.95$

$y=-0.8$

Therefore

$\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1$

$\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}$

$\frac{x^2}{3^2} =1-0.2089795918$

$X^2 =3^2(1-0.2089795918)$

$X^2 =7.119183674$

$X =\sqrt{7.119183674}$

$X =2.66817984$

Therefore the width of the given stream is

$W_s=2.66817984*2$

$W_s=5.33635968$

$W_s \approx5.3$

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3 years ago

Jack’s first weight increased by 20% and then his new weight decreased by 25%. His final weight is what percent of his beginning

ElenaW [278]

Lets suppose his initial weight was 60 kilograms

A gain of 20% would make his new eight 60 + 20*60/100

= 60 + 12

= 72 kg

he lost 25% of this:-

= 72 - 25 * 72/100 = 54 kg

This = (54/60) * 100 = 90% of his beginning weight Answer

8 0

3 years ago

IgorLugansk [536]

Answer:

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4 0

3 years ago