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prohojiy [21]
3 years ago
6

What is a strategy i could use to compare 2/6 and 5/8

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0
2/6 x 4 = 8/24
5/8 x 3 = 15/24

8/24 < 15/24

Hope this helped
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What’s the missing factor?
Vesna [10]

The missing factor is 1 5/8

<u>Step-by-step explanation:</u>

Let us consider the missing factor has 'x'

The given expression is 4 1/2 - x = 2 7/8

<u>To find x :</u>

The first step is to bring all the constant terms on on side and x on the other side,

⇒ 4 1/2 - 2 7/8 = x

Now, the numbers are in improper fraction (mixed fraction). So you have to convert them into proper fraction.

To convert the improper fraction 4 1/2 into proper fraction,

Multiply the denominator 2 with 4 and the result 8 is added with the numerator 1.

⇒ 4 1/2 = 9/2.

To convert the improper fraction 2 7/8 into proper fraction,

Multiply the denominator 8 with 2 and the result 16 is added with the numerator 7.

⇒ 2 7/8 = 23/8.

Now replace them in the given expression. The expression becomes as :

⇒ (9/2) - (23/8) = x

Cross multiply 2 and 8,

⇒ (72 - 46) / 16 = x

⇒ 26 / 16 = x

⇒ 13/8 = x

The x value is 13/8. You have to convert it into mixed fraction (since the question is given in the form of mixed fraction).

<u>To convert into mixed fraction,</u>

Divide 13 by 8 and write them in the form of Quotient (Reminder / Divisor).

⇒ 13 ÷ 8

⇒ 1 (quotient)

⇒ 5 (remainder)

The divisor is 8.

Therefore, x = 13/8 can be written as 1 5/8.

The missing factor is 1 5/8.

8 0
4 years ago
Refer to the isosceles trapezoid shown. Find m(BC)
patriot [66]

Answer:

answer is 9cm

opposite side of trapezium are equal

hopes this helps u

5 0
3 years ago
What’s the class width
aksik [14]

Answer:

4

Step-by-step explanation:

Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:

CW = UCL - LCL

Where,

CW= Class width

UCL= Upper class limit

LCL= Lower class limit

From the table above:

For class 1, CW = 64 - 60 = 4

For class 2, CW = 69 - 65 = 4

For class 3, CW = 74 - 70 = 4

For class 4, CW = 79 - 75 = 4

For class 5, CW = 84 - 80 = 4

Therefore, the class width of the grouped data = 4

6 0
3 years ago
Hello I'm Chloe Can you help me, Thank you :)
andrew-mc [135]

Answer:

b is correct

Step-by-step explanation:

3 0
3 years ago
Solve the equation 2 + x/-10 = 2/5
Delvig [45]

It's x=16

That would be the answer

3 0
3 years ago
Read 2 more answers
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