Answer:
B) 174.01 feet
Step-by-step explanation:
The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
cos(63°) = (79 ft)/(web length) . . . . . substitute given values
Solving for web length, we have ...
web length = (79 ft)/cos(63°) ≈ 174.01 ft
His web line must be 174.01 ft long.
