Answer:
A) AUG GAG GGU
B) N-MET-GLU-GLY-HIS
C) 10 amino acids
D) The stop codon here is UAA, instead of UAG. If a tryptophane residue is added where the stop codon is, the GEN polypeptide would be longer
Explanation:
First we must obtain the the complementary chain or mRNA
A) AUG start codon is complementary to DNA TAC triplet, and GAG is complementary to CTC, and GGU to CCA (running from left to right towards 5'DNA direction (AAGCGGATACCTCCCAGTAGATGCTCCGGGGCTAGTGATTTCGAAC-5)
B) TAC corresponds to Methionine, GAG to Glutamate, GGU to Glycine, and CAU to Histidine
C) UAA is the stop codon, that is complementary where the DNA triplet is ATT. From AUG to UAA, we can have 10 amino acids transcribed
D) If a trp is included where the stop codon is UAA, then the mRNA would be longer with a consequent traduction of a longer GEN polypeptide
You got me all the way fuqed
up son!
Since prokaryotic cells are haploid, they have the ability to adapt faster to changing environmental conditions than eukaryotic cells.
<h3>What are prokaryotic cells?</h3>
Prokaryotic cells are cells that are characterized by the absence of a nucleus or any other membrane-bound organelles.
On the other hand, eukaryotic cells have the presence of a membrane-bound nucleus that stores their genetic material.
Another important feature of prokaryotic cells is that they are haploid in nature i.e. they do not have chromosomes that occur in homologous pairs and have just one chromosome.
Therefore, it can be said that because prokaryotic cells are haploid, they have the ability to adapt faster to changing environmental conditions than eukaryotic cells.
Learn more about prokaryotic cells at: brainly.com/question/18348786
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Answer:
b
Explanation:
this is because Invasive species are frequently generalists in terms of food, or habitat needs, have fewer predators in their introduced environments and are better able to exploit disturbances than their native competitors.
