Answer:
Area of a trapezoid = ½(a + b)h, where a and b are the lengths of the parallel sides and h is its height.
From your information 20 = ½(2z + 3 + 6z – 1)z = ½(8z + 2)z = z(4z + 1)
Solve 20 = 4z² + z which is 0 = 4z² + z – 20 using the quadratic formula
Step-by-step explanation:
hours each day.
Step-by-step explanation:
The given function models the number of cars that are put through a quality control test each hour at a car production factory.
The given function is
We need to find the number of hours does the quality control facility operate each day.
Rewrite the given function it factored form.
Taking out the common factors from each parenthesis.
The factored form of given function is c(t)=-(t-10)(t+2).
Equate the function equal to 0 to find the x-intercept.
Number of hours cannot be negative. So from t=0 to t=10 quality control facility operate the cars.
Therefore the quality control facility operates for 10 hours each day.
Answer:
The amount Dave got after 3 wins and 2 loose is $843.75. The order of win and loose doesn't matter.
Step-by-step explanation:
- We are given with a word problem
- We are asked to find the amount he had after 5 hands
- We can do this in two steps
Step 1 : Identifying the percentages
Step 2 : Finding the amount left
Step 1 of 2
We are given with a word problem. He bets 50% of his money. If he wins he get his bet, if he loose he will loose the money too. If he wins he will get the money as 150%.
That is, 1.5
If he loose he will loose money by 50%
That is, 0.50
Step 2 of 2
The amount got after 5 hands with 3 wins and 2 loose is,
Midpoint is the the sum of the two then divided by 2.
So add (-7 + 4i) and (3 - 2i)
Adding them will get you (-4 + 2i). Then you have to divide by 2 which will give you (-2 + i)
Answer:
$15,746.400
Step-by-step explanation:
The computation of the car value in the year 2010 is shown below:
Since the new car brought in the year of 2006 at $24,000
And, it would be depreciation by 10%
So, in the year 2010 the car value would be
= $24,000 × (1 - 0.10)^4
= $24,000 × 0.9^4
= $15,746.400