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defon
3 years ago
5

A lazy high school senior types up application and envelopes to and different colleges, but puts the applications randomly into

the envelopes. What is the expected number of applications that went to the right college?
Mathematics
1 answer:
djyliett [7]3 years ago
7 0

Complete Question:

A lazy high school senior types up application and envelopes to n different colleges, but puts the applications randomly into the envelopes. What is the expected number of applications that went to the right college?

Answer:

The expected number is 1

Step-by-step explanation:

In order to get a better understanding of the answer above let explain some terms

Expected Number (Value) :

The expected value (EV) is an anticipated value for an event.In statistics and probability analysis, the expected value is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values.

The basic expected value formula is the probability of an event multiplied by the amount of times the event happens: (P(x) * n).

from the formula P(x) is likelihood that application would reach the right college = 1/n

and n = is the number of applications

hence the expected number of application = 1/n × n = 1

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LuckyWell [14K]

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Answer:

  4. (d) 4.38 in³

  5. (b) 19 gallons

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Step-by-step explanation:

4. The equation can be rearranged to find the compressed volume.

Multiply both sides by the compressed volume:

  (compression ratio)×(compressed volume) = (expanded volume)

Divide both sides by the compression ratio:

  (compressed volume) = (expanded volume)/(compression ratio)

Fill in the numbers and do the arithmetic.

  compressed volume = 46.0 in³/(10.5/1) = 4.38 in³

The compressed volume is about 4.38 in³.

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5. The area to be covered is 3170 ft². We want to cover it twice, so the total area we want to cover is 2×3170 ft² = 6340 ft². One gallon of paint covers 350 ft². We want to find the smallest integer number of gallons n such that ...

  n×(350 ft²) ≥ 6340 ft²

Dividing by the coefficient of n, we have ...

  n ≥ 6340/350 ≈ 18.11

The smallest integer value of n is 19. 19 gallons of paint will be needed.

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6. The quantity of sand needed (q) is proportional to the area to be covered, so we have ...

  q/(400 yd²) = (1.6 yd³)/(100 yd²)

Multiplying both sides of this equation by 400 yd² gives ...

  q = (1.6 yd³)(400/100) = 6.4 yd³

6.4 yd³ of sand will be needed.

8 0
3 years ago
Find the length of the side of rhoumbus whose diagonals are of length 6cm and 8cm.​
Artist 52 [7]

Answer:

In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -

one side of triangle =  6/2 =3 (half of the diagonal)

other side = 8/2 = 4

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3 ^2 + 4^2 = c^2

9+16 = c^2

c^2=25

c = \sqrt{25} = 5

the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !

6 0
3 years ago
2. Graph the system of inequalities. Make sure your solution area is clear in your graph.
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6 0
3 years ago
Read 2 more answers
What is the circumference of a circle circumscribed around a rectangle with sides 7 cm and 24 cm?
Tomtit [17]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
What is 111*4=,please help
ollegr [7]
111×4 would exactly be 444 very simple 

Hope this helps :)
7 0
4 years ago
Read 2 more answers
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