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3 years ago

Find the length of the side of rhoumbus whose diagonals are of length 6cm and 8cm.

Mathematics

1 answer:

Artist 52 [7]3 years ago

6 0

Answer:

In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -

one side of triangle = 6/2 =3 (half of the diagonal)

other side = 8/2 = 4

a^2 + b^2 = c2

3 ^2 + 4^2 = c^2

9+16 = c^2

c^2=25

c = $\sqrt{25}$ = 5

the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !

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Serjik [45]

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First, find the zeros:

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x = $\frac{3}{4}$ x = $\frac{1}{2}$

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------ $\frac{1}{2}$ ------ $\frac{5}{8}$ ------ $\frac{3}{4}$ ------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!

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Answer: x ≤ $\frac{1}{2}$ or x ≥ $\frac{3}{4}$

Interval Notation: (-∞, $\frac{1}{2}$ ] U [ $\frac{3}{4}$ , ∞)

Graph: ←------ $\frac{1}{2}$ $\frac{3}{4}$ --------→

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3 years ago

Find the length of the side of rhoumbus whose diagonals are of length 6cm and 8cm.​

Find the length of the side of rhoumbus whose diagonals are of length 6cm and 8cm.