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ki77a [65]
3 years ago
13

Find the length of the side of rhoumbus whose diagonals are of length 6cm and 8cm.​

Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:

In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -

one side of triangle =  6/2 =3 (half of the diagonal)

other side = 8/2 = 4

a^2 + b^2 = c2

3 ^2 + 4^2 = c^2

9+16 = c^2

c^2=25

c = \sqrt{25} = 5

the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !

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Answer:

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Step-by-step explanation:

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7 0
2 years ago
5n(3n+8) ..? I don't understand
SSSSS [86.1K]
You have ti distribute the 5n into the brackets. 

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5 0
3 years ago
Find the slope of the tangent to y= -7Sin(x)+2cos(x) at x= 3π/4
BaLLatris [955]
Y = -7sin(x) + 2cos(x)
y = -7sin(3π/4) + 2cos(3π/4)
y = -7sin(9.42/4) + 2cos(9.42/4)
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6 0
3 years ago
Look at the picture down below and help me out?
d1i1m1o1n [39]
Is 20 and answer because I did this on a calculator and this is the only one to me that would make since
6 0
3 years ago
1/7 ÷ 2 =
e-lub [12.9K]

Hey there!

1/7 ÷ 2

= 1/7 ÷ 2/1

1/7 ÷ 2/1

Revert 2/1 to 1/2

1 × 1 / 7 × 2

1 × 1 = 1 ⬅ your NUMERATOR (top number)

7 × 2 = 14 ⬅ your DENOMINATOR (bottom number)

1(1) / 7(2) = 1/14

Answer: 1/14 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0
3 years ago
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