Triangle ABD is i<span>nscribed in circle and </span>has hypotenuse as circle's diameter so angle ABD must be 90°
Since it is parallelogram, ∠ABD = ∠BDC = 90° and it is given that ∠ADB = 30°
So we have ∠CDO = ∠CDB + ∠ADB = 30° + 90° = 120°
Final answers: ∠CDO = 120° and ∠ABD = 90°
Answer:
Option B False
Step-by-step explanation:
we know that
The <u>Cavalieri's principle</u> states that if two or more figures have the same cross-sectional area at every level and the same height, then the figures have the same volume
therefore
The cross-sectional area at every level must be the same
so
The statement is False
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Answer:
its C
Step-by-step explanation:
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