Every difference of squares problem can be factored as follows: a2 – b2 = (a + b)(a – b) or (a – b)(a + b). So, all you need to do to factor these types of problems is to determine what numbers squares will produce the desired results.
I think the answer is a btw hoped it helped
Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
Answer:
12
Step-by-step explanation:
h(x) = f(g(x))
Using chain rule:
h'(x) = f'(g(x)) g'(x)
h'(1) = f'(g(1)) g'(1)
h'(1) = f'(2) g'(1)
h'(1) = -4 × -3
h'(1) = 12
Answer:
<h2>The first graph in the second image is an odd function.</h2>
Step-by-step explanation:
An odd function has a graph that it's symmetric about the origin, that is, the origin is like a mirror. In other words, the graph of an odd function has a specific symmetry about the origin.
So, we have to look for those graph that has symmetrical points in opposite quadrants, I and III or II and IV.
You can observe that the first graph of the second image has this behaviour. You can see that the points are symmetrical across the origin. If you graph a line defined as y=-x, you will observe that such line acts like a mirror.
Therefore, the odd function is the first graph in the second image.
