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3 years ago

How many solutions does the system have? (x+2y=2 2x + 4y = -8

Mathematics

2 answers:

SIZIF [17.4K]3 years ago

6 0

Answer:

<h2>0 - no solution</h2>

Step-by-step explanation:

$\text{Let}\\\\\left\{\begin{array}{ccc}ax+by=c\\dx+ey=f\end{array}\right\\\\\text{in its simplest form, i.e. that a and b, d and e are relatively first}$

$\text{if}\ a=d,\ b=e,\ c=f,\ \text{then a system of equations has infinitely many solutions}\\\\\text{Example:}\\\\\left\{\begin{array}{ccc}x+3y=6\\-2x-6y=-12&\text{divide both sides by (-2)}\end{array}\right\\\\\left\{\begin{array}{ccc}x+3y=6\\x+3y=6\end{array}\right$

$\text{if}\ a=d,\ b=e,\ c\neqf,\ \text{then the system of equations has no solution}\\\\\text{Example:}\\\\\left\{\begin{array}{ccc}3x+9y=12&\text{divide both sides by 3}\\x+3y=1\end{array}\right\\\\\left\{\begin{array}{ccc}x+3y=4\\x+3y=1\end{array}\right$

$\text{In other cases it has one solution.}$

$\text{We have:}\\\\\left\{\begin{array}{ccc}x+2y=2\\2x+4y=-8&\text{divide both sides by 2}\end{array}\right\\\\\left\{\begin{array}{ccc}x+2y=2\\x+2y=-4\end{array}\right\\\\\text{Conclusion:}\\\\\text{The system of equations has no solution.}$

$\text{Now I will show it}$

$\left\{\begin{array}{ccc}x+2y=2\\x+2y=-8&\text{change the sings}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}x+2y=2\\-x-2y=8\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=10\qquad\bold{FALSE}$

pogonyaev3 years ago

3 0

Answer:

Step-by-step explanation:

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Fed [463]

Answer:

Therefore the of blue in the second urn is 4.

Step-by-step explanation:

Let second urn contain x number of blue ball .

Urn Red Ball Blue Ball Total Ball

1 4 6 10

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Getting a red ball from first urn is $P(R_1)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{4}{10}$

Getting a blue ball from first urn is $P(B_1)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {6}{10}$

Getting a red ball from second urn is $P(R_2)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{16}{16+x}$

Getting a blue ball from second urn is $P(B_2)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {x}{16+x}$

Getting two red balls from first and second urn is $=\frac{4}{10}\times \frac{16}{16+x}$

$=\frac{32}{5(16+x)}$

Getting two blue balls from first and second urn is $=\frac{6}{10}\times \frac{x}{16+x}$

$=\frac{3x}{5(16+x)}$

The probability that both balls are the same in color is $=\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}$

Given that the probability that both balls are the same in color is 0.44.

According to the problem,

$\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}=0.44$

$\Rightarrow \frac{32+3x}{5(16+x)} =0.44$

$\Rightarrow \frac {32+3x}{(80+5x)} =0.44$

$\Rightarrow 32+3x =0.44(80+5x)$

$\Rightarrow 32+3x =35.2 +2.2x$

$\Rightarrow 3x -2.2 x= 35.2 -32$

$\Rightarrow 0.8x= 3.2$

$\Rightarrow x = 4$

Therefore the of blue in the second urn is 4.

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3 years ago

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Answer:

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Answer:

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Step-by-step explanation:

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The parent function, f(x) = x, might undergo the following series of transformations to produce the graph: Reflect over the y-axis, vertical stretch by a factor of 2, and then shift up 6 units.

<h3>What is geometric transformation?</h3>

It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.

The converted function, when compared to the original function, will be obtained as y = -2x + 6 if we plot it on the coordinate plane.

The only method by which the provided graph may be converted to the coordinates specified in the problem is;

Reflect over the y-axis, multiply the vertical stretch by two, and then move up six units.

Thus, the parent function, f(x) = x, might undergo the following series of transformations to produce the graph: Reflect over the y-axis, vertical stretch by a factor of 2, and then shift up 6 units.

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