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fgiga [73]
3 years ago
7

4.in a recent year, the population of california was about 2.52x10^7 people. its land area is about 4.05x10^5 km^2. what was the

average number of people per square kilometer?
0.62x10^5
6.2x10^1
0.62x10^14
6.2x10^9
Mathematics
2 answers:
rjkz [21]3 years ago
7 0
As given;

2.52x10^7 people are living in <span>4.05x10^5 km^2 area. then for 1km^2, the number of people can be calculated as:
people in 1km^2 = (2.52x10^7) / (</span><span>4.05x10^5)
=0.62x10^2
or
=6.2x10^1</span>
stepan [7]3 years ago
4 0

Answer:

1.d

2.a

3.c

4.b

:) just took the practice got its 100% thee answer

God bless you guys

and thank u the person above me i needed help on that one only and you really helped me

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pashok25 [27]

Answer:

320√5 it simpleflied

Step-by-step explanation:

4 0
2 years ago
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If you could show as much work as possible that would be amazing!!
Nikitich [7]

Answers:

<u>Reduce:</u>

Here we gave to simplify the expressions:

9) x^{2}+7x+\frac{12}{x^{2}}+11x+28

Grouping similar terms:

(x^{2}+\frac{12}{x^{2}})+(18x+28)

Applying common factor x^{2} in the first parenthesis and common factor 2 in the second parenthesis:

x^{2}(1+\frac{12}{x^{4}})+2(9x+14) This is the answer

11) y^{3}+\frac{27}{y^{2}}+2y-3

Rearranging the terms:

(y^{3}+2y)+(\frac{27}{y^{2}}-3)

Applying common factor y in the first parenthesis and common factor 3 in the second parenthesis:

y(y^{2}+2)+3(\frac{9}{y^{2}}-1) This is the answer

<u>Multiply:</u>

19) (\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})

Multiplying both fractions:

\frac{36 a^{9}u^{7}c^{4}}{315 c a^{13}u^{8}}

Dividing numerator and denominator by 3 and simplifying:

\frac{12 c^{3}}{105 c a^{4}u} This is the answer

21) (x-\frac{3}{x}-7)(x^{2}-9x+\frac{35}{x^{2}}-18)

(\frac{x^{2}-3-7x}{x})(\frac{x^{4}-9x^{3}+35-18x^{2}}{x^{2}})

Operating with cross product:

x^{2} (x^{2}-3-7x) x(x^{4}-9x^{3}+35-18x^{2})

x^{9} -9x^{8} -18x^{7}+35x^{5}-7x^{8}  +63x^{7}+126x^{6}-245x^{4}-3x^{7}+27x^{6}+54x^{5}-105x^{3}

Grouping similar terms and factoring:

x^{9}-2(8x^{8}+21x^{7} )+153x^{6}+89x^{5}-5(49x^{4}+21x^{3}) This is the answer

<u>Divide:</u>

29) \frac{\frac{k^{6}}{x^{2}}}{\frac{2k^{4}}{3x^{6}}}

\frac{3k^{6}x^{6}}{2x^{2}k^{4}}

Simplifying:

\frac{3}{2} k^{2}x^{4} This is the answer

33) \frac{\frac{x+5}{x+1}}{\frac{x^{2}+11x+30}{x^{2}+3x+2}}

\frac{(x+5)(x^{2}+3x+2)}{(x+1)(x^{2}+11x+30)}

Factoring numerator and denominator:

\frac{(x+5)(x+2)(x+1)}{(x+1)(x+6)(x+5)}

Simplifying:

\frac{x+2}{x+6} This is the answer

37) \frac{\frac{x-10}{x+13}}{\frac{x^{3}-1000}{x^{2}+15x+21}}

\frac{(x-10)(x^{2}+15x+21)}{(x+13)(x^{3}-1000)}

Applying the distributive property in numerator and denominator:

\frac{x^{3}+15x^{2}+21x-10x^{2}-150x-210}{(x+13)(x^{4}-1000x+13x^{3}-13000)}

Grouping similar terms and factoring by common factor:

-\frac{5x(x^{2}-129)(x^{2}-42)}{1000x^{3} (x+13)(x-13)}

Dividing by 5 in numerator and denominator and simplifying:

-\frac{(x^{2}-129)(x^{2}-42)}{200x^{2}(x+13)(x-13)} This is the answer

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2.50 divide by 7= .36 cents for each pound
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tangare [24]
Ax+by=c is the standard form
you are given the slope and a point, so first write the equation in point-slope form:
y-(-3)=2/3(x-6)
expand the equation: y+3=(2/3)x-4
(2/3)x-y=7 is the standard form
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2 years ago
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The length of a rectangle is 6 meters more than its width. If the area is 135 square meters, what is its width?
Novay_Z [31]
Length = width +6

L * (L - 6) = 135

L^2 - 6L = 135

L^2 - 6L -135 = 0

Length = 15
Width = 9


4 0
3 years ago
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