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Gnom [1K]
3 years ago
10

Marco model bridge is 9 centimetres taller than joes model bridge. if Joe's bridge is 31 centimetres tall. write an Equation tha

t could be used to find the height
Mathematics
2 answers:
Damm [24]3 years ago
6 0
9 + 31 = x. If Macros bridge is 9 centimeters taller than 31, you just have to do 9 + 31.
Lelechka [254]3 years ago
6 0
All you need to do is use the formula which is A = b x h. So, to solve, you just need to multiply 9 by 31 and I think that equals x. I'm not going to give you the answer because I want to see if you can solve it out yourself.

Update: I think I did the formula wrong. I think it's the user above who put the correct formula. Yeah, so I think you just add 9 and 31.


Anyways, just add 9 and 31 to get your answer.
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The vertex (5,39)

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(5,39) vertex means that  <span>Buying five of each type of plant costs $39, which is the lowest possible cost.</span>
3 0
3 years ago
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On a piece of paper, graph this system of inequalities. Then determine which region contains the solution to the system.
Mashutka [201]

we have

y\leq \frac{1}{4}x+3 ----> inequality 1

The solution of the inequality 1 is the shaded area below the solid red line

The solution is the region D and region C

y\geq-x+5 -----> inequality 2

The solution of the inequality 2 is the shaded area above the solid blue line

The solution is the region B and region C

The solution of the system is the common area

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see the attached figure

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the answer is the option C

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3 0
3 years ago
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creativ13 [48]

Answer:

-6 k +5

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Think of k is apples

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Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

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\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

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-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0
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8 0
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