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GuDViN [60]
3 years ago
10

An object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seco

nds. Which cosine function may be used to model the height of the object?
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

y=2\text{cos}((\frac{2\pi}{3})t)

Step-by-step explanation:

We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.

We know that standard form of cosine function is y = A\cdot \text{cos}(Bt-C)+D, where,

|A| = Amplitude,

Period = \frac{2\pi}{|B|},

C = Phase shift,

D = Vertical shift.

Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, A = 2.

Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by \frac{2\pi}{|B|}, therefore, we can write \frac{2\pi}{|B|}=3, therefore, B = \frac{2\pi}{3}.

We haven't been given any information about phase and mid-line, we can assume the values of C and D to be zero .

Therefore, our function required function would be y=2\text{cos}((\frac{2\pi}{3})t).

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Answer:

1/5

Step-by-step explanation:

pick any points, for example (6, -1) and (11, 0)

slope is m= (y2-y1) / (x2-x1) = -1-0 / 6-11 = -1 / -5 = 1/5

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3 years ago
What is the area, please help me!
exis [7]

Answer:

30ft2. (C.)

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7 0
2 years ago
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The quadrilateral shown is rotated 90° clockwise about the origin. In which quadrant is the image of the quadrilateral located?
Viktor [21]

Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

4 0
2 years ago
Harry church borrowed 17,500.00 at 6.5% exact interest. He had to pay back a maturity value of 17,873.97 to pay off the loan. Wh
kirill [66]

Answer:the term of the loan is approximately 4 months

Step-by-step explanation:

The term of the loan means the period for which the loan was given.

We would apply the formula for simple interest which is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

From the information given

P = 17500

R = 6.5%

I = total amount paid - principal

I = 17,873.97 - 17,500.00 = 373.97

Therefore

373.97 = (17500 × 6.5 × T)/100

373.97 = 1137.5T

T = 373.97/1137.5

T = 0.32 years

Converting to months, it becomes

0.32 × 12 = 3.84

Approximately 4 months.

3 0
3 years ago
If r || s and m 5 = 65°, what is m 1?
lesya [120]

1 and 5 are corresponding angles, so both have the same measure:

m 1 = m 5

m 1 = 65º


Answer:  option D. 65º.


I hope this helps. =)

8 0
3 years ago
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