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GuDViN [60]
3 years ago
10

An object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seco

nds. Which cosine function may be used to model the height of the object?
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

y=2\text{cos}((\frac{2\pi}{3})t)

Step-by-step explanation:

We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.

We know that standard form of cosine function is y = A\cdot \text{cos}(Bt-C)+D, where,

|A| = Amplitude,

Period = \frac{2\pi}{|B|},

C = Phase shift,

D = Vertical shift.

Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, A = 2.

Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by \frac{2\pi}{|B|}, therefore, we can write \frac{2\pi}{|B|}=3, therefore, B = \frac{2\pi}{3}.

We haven't been given any information about phase and mid-line, we can assume the values of C and D to be zero .

Therefore, our function required function would be y=2\text{cos}((\frac{2\pi}{3})t).

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Segments AB, DC and Ec intersect at point C. Angel DCE measures 148. Find the value of x.
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The image is attached.

Answer:

x = 16°

Step-by-step explanation:

Segment AB, segment DC and segment EC all intersect at point C.

Here, we are told angle DCE measures 148°.

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Which means, x+x+148 = 180

Solving for x, we have:

x+x+148 = 180

2x + 148 = 180

2x = 180 - 148

2x = 32

x = \frac{32}{2}

x = 16°

The value of x is 16°

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Answer:

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Step-by-step explanation:

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Then the second integer will be (n + 1).

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