1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GuDViN [60]
3 years ago
10

An object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seco

nds. Which cosine function may be used to model the height of the object?
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

y=2\text{cos}((\frac{2\pi}{3})t)

Step-by-step explanation:

We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.

We know that standard form of cosine function is y = A\cdot \text{cos}(Bt-C)+D, where,

|A| = Amplitude,

Period = \frac{2\pi}{|B|},

C = Phase shift,

D = Vertical shift.

Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, A = 2.

Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by \frac{2\pi}{|B|}, therefore, we can write \frac{2\pi}{|B|}=3, therefore, B = \frac{2\pi}{3}.

We haven't been given any information about phase and mid-line, we can assume the values of C and D to be zero .

Therefore, our function required function would be y=2\text{cos}((\frac{2\pi}{3})t).

You might be interested in
How much does a glass cube with a side of 5-cm weigh if 1cm3 of glass weighs 2 2/5 grams?
PtichkaEL [24]

The weight of galss cube with side 5 cm is 300 grams

<em><u>Solution:</u></em>

A glass cube is of side length 5 cm

Let us first find the volume of glass cube

<em><u>The volume of cube is given as:</u></em>

volume = (side)^3\\\\volume =5^3 = 125

Thus volume of cube is 125 cm^3

Given that,

1 cm^3 = 2\frac{2}{5} \text{ grams }\\\\1 cm^3 =\frac{12}{5} \text{ grams}

So, weight of 125 cubic centimeter of glass cube is found by multiplying weight of 1 cubic centimeter of glass cube by 125

\text{ Weight of 125 } cm^3 \text{ cube } = \text{ Weight of 1 } cm^3 \text{ cube } \times 125

\text{ Weight of 125 } cm^3 \text{ cube } = \frac{12}{5} \times 125 = 25 \times 12 = 300

Thus weight of galss cube with side 5 cm is 300 grams

3 0
3 years ago
Read 2 more answers
What’s £8 in ratio 1:1 I’m stuck ?
Varvara68 [4.7K]
£4:£4 is the answer.
5 0
3 years ago
Write an algebraic expression to represent the following verbal expression
DaniilM [7]
The answer is B. They are saying to cube the difference therefore you have (x-43) cubed
4 0
3 years ago
Read 2 more answers
Please help me for the love of God if i fail I have to repeat the class
Elena-2011 [213]

\theta is in quadrant I, so \cos\theta>0.

x is in quadrant II, so \sin x>0.

Recall that for any angle \alpha,

\sin^2\alpha+\cos^2\alpha=1

Then with the conditions determined above, we get

\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35

and

\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}

Now recall the compound angle formulas:

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta

\sin2\alpha=2\sin\alpha\cos\alpha

\cos2\alpha=\cos^2\alpha-\sin^2\alpha

as well as the definition of tangent:

\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}

Then

1. \sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}

2. \cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}

3. \tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}

4. \sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}

5. \cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}

6. \tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7

7. A bit more work required here. Recall the half-angle identities:

\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2

\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2

\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}

Because x is in quadrant II, we know that \dfrac x2 is in quadrant I. Specifically, we know \dfrac\pi2, so \dfrac\pi4. In this quadrant, we have \tan\dfrac x2>0, so

\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32

8. \sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}

6 0
3 years ago
How can you identify a linear nonproportional relationship from a table, a graph, and an equation?
Zarrin [17]
On-proportional linear relationships can be expressed in the form y = mx + b, where b is not 0, m represents the constant rate of change or slope of the line, and b represents the y-intercept. The graph of a non-proportional linear relationship is a straight line that does not pass through the origin.
3 0
4 years ago
Other questions:
  • Month 0 1 2 3 length 5 6 7 8 input output table graph
    11·1 answer
  • Simplify please help.
    6·1 answer
  • What is the ratio of the circumferences for two circles with areas 6pi m2 and 150pi m2?
    15·2 answers
  • Find two numbers whose ratio is 3:7 and whose sum is 150
    8·1 answer
  • The given line passes through the points (0, −3) and (2, 3). What is the equation, in point-slope form, of the line that is para
    6·2 answers
  • Find the measure of each exterior angle of a regular 56-gon. Round to the nearest tenth.
    7·1 answer
  • Find the area of the sector.
    13·1 answer
  • COMPLETE<br> h<br> 50<br> The sum n(n+6) =<br> +<br> 1575<br> RETRY
    15·1 answer
  • Joses his yearly wages were $50 more than marks, so he earned 16,815.43. Yet he said his taxes are the same as marks. Is he righ
    7·1 answer
  • The record low temperature for a town is -13F. Yesterday, it was 6F. What is the difference between the absolute values of these
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!