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Semmy [17]
3 years ago
8

Build an equation with at least three different operations that has solution x=2

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer: (10x+7)/2 = -13/2

This is not the only answer possible. There are infinitely many possible answers.

=================================

Explanation:

We start with the given equation x = -2

Multiply both sides by some number. I'll pick 10

So if we multiply both sides by 10, we get

10*x = 10*(-2)

10x = -20

Now let's add something to both sides. Let's say we add 7 to both sides

10x+7 = -20+7

10x+7 = -13

Finally, let's divide both sides by 2

(10x+7)/2 = -13/2

You could keep going to add, subtract, multiply, or divide both sides by some number. This process can continue indefinitely. I'll stop here since we have three operations done.

-------------------

If we were to solve (10x+7)/2 = -13/2, we would get to x = -2

To solve (10x+7)/2 = -13/2, we follow the steps done in the previous section in reverse.

So we'll undo the "divide both sides by 2" operation by multiplying both sides by 2.

Then we'll undo the "add 7 to both sides" operation to subtract 7 from both sides

Lastly, we'll undo the "multiply both sides by 10" by dividing both sides by 10.

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4 0
3 years ago
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 46.046.0 and
Gala2k [10]

Answer:

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is 0.10

Step-by-step explanation:

The Uniform Distribution, also known as Rectangular Distribution, is a type of Continuous Probability Distribution. It has a continuous random variable restricted to a finite interval and its probability function has a constant density during this interval.

The formula of probability if given by:

f(x)=

\left \{ {{\frac{1}{b-a}; \ a \leq x \leq b  } \atop {0}; \ x \ otherwise } \right.

In this exercise a= 46.0 and b= 56.0

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is:

\int\limits^{51.25}_{50.25} {\frac{1}{56-46} } \, dx = \int\limits^{51.25}_{50.25} {\frac{1}{10} } \, dx = \frac{1}{10} \times (51.25 - 50.25)=\frac{1}{10}=0.1

7 0
3 years ago
What is the sum or difference?
dlinn [17]
1. Ans: Option (B) -6x^4

Explanation:
Given: 2x^4 - 8x^4
Take the common out:
=> x^4(2 - 8)

Hence: => [tex]-6x^4[/tex] (Option B)

2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6<span> quadratic trinomial 

Explanation:
</span>Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 
13x^2 - 4x^2 - 12x + 6
=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: 3.1x^2 +6.0x + 0.3<span>
Endler's guppies:   </span>4.2x^2 - 5.2x + 1.0
(add both)
-----------------------------------------------------------------
Total number:          7.3x^2 +0.8x + 1.3
-----------------------------------------------------------------
Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
Therefore,
Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
=> Final area of the Yard = 2x^2(133 - 18 \pi) (Option D)

6. Ans: Option (A) 56x^2

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = 60x^2

Now the area of the stadium:
Area of the stadium = 1x * 4x = 4x^2

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= 60x^2 - 4x^2
=> Final area of the lot = 56x^2 (Option A)

-i
4 0
3 years ago
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Dmitrij [34]

Answer:

3/8 of a page

Step-by-step explanation:

3/4=2 minutes

3/8 pages in a minute

You take 3/4 and divide by 2 to get 3/8

7 0
3 years ago
Simplify 2-1 + 5* 4 + 11
kozerog [31]

Answer:32

Step-by-step explanation:firs we multiply 5*4 =20 .then we subtract 2-1=1 add those numbers 20+1=21 and then add 11 which equals 32

4 0
3 years ago
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