Question

Your drawer contains 6 gold earrings and 7 silver earrings. You randomly choose an earring. Without replacing the first, you choose a second earring. What is the probability that both earrings are silver

Answer 1

Answer:

The probability that both earrings are silver is 0.27.

Step-by-step explanation:

Basically, we have to pick in a such a way that the first earring is a silver earring and the second one is also a silver earring.

Constituents of the box= 7 silver, 6 gold.

Probability=$\frac{No. Of Favorable Outcomes}{Total No. Of Outcomes}$

Therefore, probability of picking up a silver earring in the first attempt(A)= $\frac{7}{13}$  

As we have picked up, one earring from the bag, the no. of silver earrings have been decreased by 1 as have the total no. of earrings.

Therefore, the total no. of earrings now=12

No. of silver earrings in the bag now=6

Probability of picking up a silver in the second attempt after the above first attempt(B)=$\frac{6}{12}$

P(A∩B)=P(A)*P(B)

            =$\frac{7}{13}$ x $\frac{6}{12}$

             =$\frac{7}{26}$

              =0.269

The probability that both earrings are silver is 0.27.