Answer:
Step-by-step explanation:
Given that KLMN is a trapezium.
K has coordinates (0,0), L(2a,0), M(2d,2c) and N(2b,2c)
R is the mid point of KN
Hence coordinates of R will be using mid point formula (x1+x2/2, y1+y2/2)
= (a,c)
Similarly S is mid point of segment LM.
Hence S = (a+d,c)
The slope of SL is = (y2-y1)/(x2-x1) = (a-d)/-c=(d-a)/c
The slope of RS = (c-c)/d =0
The slope of NM = (2c-2c)/(2b-2d) = 0
Since slope of RS = slope of NM
We get RS is parallel to NM
Already NM is parallel to KL because bases of trapezium
Hence RS is parallel to both the bases.
