Answer:
your answer is D
Step-by-step explanation:
Answer:
in the space of x we'll equate it to 5-y
2(5-y)+3y=12
10-2y+3y=12
-2y+3y=12-10
y=2
subt y into first equation (x=5-y)
x=5-2
x=3
Answer:
(3,0)
Step-by-step explanation:
We know that x intercepts is when the graph crosses the x-axis. Thus, all x intercepts have a y value of 0. (x, 0)
Therefore, we can set y to 0 to see when the graph equals y=0 or the x-axis.
2(0)-4x=-12
-4x=-12
x=3
I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
