Answer:
Step-by-step explanation:
Domain x^2 - 9 {Solution: - infinity < x < infinity}
Interval notation (- infinity, infinity)
Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)
Interval notation (-9, infinity)
Axis interception points of x^2 - 9:
X- intercepts (3, 0) (-3, 0)
Y-intercepts (0, -9)
Vertex of x^2 - 9: Minimum (0, -9)
Solve for f:
f (x) = x^2 - 9
Step 1: Divide both sides by x.
fx / x = x^2 - 9 / x
f = x^2 - 9 / x
Answer:
f = x^2 - 9 / x
From the given table, the annual premium rate as a percentage of value insured a person at age 35 has to pay is 0.14%.
- The amount more annually a $115,000 10-year term insurance at age 35 cost Bernard than someone of the same age without health issues is option d. <u>$24</u>
Reasons:
The data in the table are presented as follows;
![\begin{tabular}{|c|c|c|}Age&Annual Insurance Premiums (per \$1,000 of face value)&\\&10-Year Term &\\&Male&Female\\35&1.40&1.36\\40&1.64&1.59\\45&2.07&2.01\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%7B%7Cc%7Cc%7Cc%7C%7DAge%26Annual%20Insurance%20Premiums%20%28per%20%5C%241%2C000%20of%20face%20value%29%26%5C%5C%2610-Year%20Term%20%26%5C%5C%26Male%26Female%5C%5C35%261.40%261.36%5C%5C40%261.64%261.59%5C%5C45%262.07%262.01%5Cend%7Barray%7D%5Cright%5D)
From the above table, we have that the amount a 35 year old without health issues will pay per $1,000 is $1.40
Therefore, the amount to be paid for $115,000 is 115 × $1.4 = $161
The amount Bernard pays = 15% more = 1.15 × $161 = $185.15
Therefore;
The amount more Bernard has to pay = $185.15 - $161 = $24.15 ≈ <u>$24</u>
Learn more about insurance premiums here:
brainly.com/question/3053945
Answer: 6.2
Step-by-step explanation: 3.1 = x/2
x/2=3.1
x/2(2)=3.1(2)
x=6.2
Answer:
The domain is 
Step-by-step explanation:
Given functions
and 
Subtract these two functions:

Plot these difference on the coordinate plane (see attached diagram). This function is defined for all vlues of x, so the domain is 
Answer:
18m
Step-by-step explanation:
Since the given traingles are similar
We get






Hence the distance across river is 18m