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Drupady [299]
3 years ago
14

A triangle has sides with lengths of

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Using the Pythagorean theorem, you would square 8, 15, and 17. 8^2 is 64. 15^2 is 225. If you add those, you get 289. Now, 17^2 is 289. Because 289=289, it is a square triangle.

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Factor completely.<br> 486 + 108z + 6x2 =
Firlakuza [10]

Answer:

  • 6(x^2 +18z +81) . . . as written
  • 6(x +9)^2 . . . . . . . . assuming a typo

Step-by-step explanation:

As the expression is written, the only factoring that can be done is to factor out the common numeric factor of 6:

  = 6(x^2 +18z +81)

__

<em>Assuming a typo in the question</em>

If we assume all variables are supposed to be "x", then the quadratic term can be further factored as a square:

  = 6(x +9)^2

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It is often handy to remember that the form of the square of a binomial is ...

  (a +b)^2 = a^2 +2ab +b^2

Here, we recognize that 18 = 2√81, so the binomial is (x +√81) = (x +9).

7 0
3 years ago
Micah is twice as old as Richard. Richard is four times as old as Ken. Ken is six years old. How old is Micah?
Lelu [443]

Answer:

Step-by-step explanation:

Micah is 48 years old.

E.

K = 6

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M = (( 6 x 4 ) x 2 )) = 48

5 0
4 years ago
Read 2 more answers
Please help with number 4
Scilla [17]

Answer:

B) 16

Step-by-step explanation:

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3 0
3 years ago
Can someone answer this ITS DUE TOMORROW
zaharov [31]

Answer:

a-x

b-/

Step-by-step explanation:

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3 0
3 years ago
Can anyone do question 25 part c? :)
inna [77]
\begin{cases}x^3\qquad\qquad\ \ \  when\ x\geq3\\5\qquad\qquad\quad \ when\  0\ \textless \ x\ \textless \ 3\\x^2-x+2\quad\ when\ x\leq0 \end{cases}\\\\\\ (a)\\ f(0)\iff x=0\implies f(x)=x^2-x+2\\\\f(0)=0^2-0+2=2\\\\(b)\\ \{f(2)\iff x=2;\ \ f(1)\iff x=1\}\implies f(x)=5\\\\ f(2)=5\quad\wedge\quad f(1)=5\\\\ f(2)-f(1)=5-5=0

(c)\\ \big\forall \limits_{ n\in R}\ n^2\geq 0\ \ \Rightarrow\ \ \big\forall \limits_{ n\in R}\ (-n^2)\leq 0 \ \ \Rightarrow\ \ x\leq0\ \ \Rightarrow\ \  f(x)=x^2-x+2\\\\f(-n^2)=(-n^2)^2-(-n^2)+2=n^4+n^2+2
5 0
4 years ago
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