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blondinia [14]
3 years ago
13

A student works for 80 hours each month and plans to work for 5 hours each day, but only on days when scheduled to work. The fun

ction / (d) - 80 -- 5d represents the number of
hours of work remaining for the month after working for d days.
Which statement is true?
A. The value of (4) is 20, and it represents the number of hours of work remaining for the month after working for 4 days.
B. The value of ? (4) is 20, and it represents the number of hours spent working over 4 days
C. The value of }(4) is 60, and it represents the number of hours of work remaining for the month after working for 4 days
D. The value of (4) is 60, and it represents the number of hours spent working over 4 days.
**pls help ASAP taking a test .
Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

C.  The value of f (4) is 60, and it represents the number of hours of work remaining for the month after working for 4 days

Step-by-step explanation:

So 5 time 4 equals 20...!

80 minus 20= 60

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Find the area. Please help im begging! ( Multiple choice )
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A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
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Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

7 0
3 years ago
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