It will save it in the pre-installed iphotos application.
Hope this helps. <span />
The answer is encryption
steganography would be hiding data, like in an image
digital forensics is the analysis done after an attack
and the last one is a security standard
Answer:
See explaination
Explanation:
#include <iostream>
using namespace std;
class Circle{
// private member variable named radius
private:
double radius;
// get function for radius
public:
double getRadius(){
return radius;
}
// set function for radius
void setRadius(double rad){
radius=rad;
}
// returning area = 3.14159 * radius * radius
double getArea(){
return (3.14159 * radius * radius);
}
};
// Sample run
int main()
{
// Declaring object of Circle
Circle myCircle;
myCircle.setRadius(5);
// printing radius of circle
cout<<"Radius of circle is: "<<(myCircle.getRadius())<<endl;
// printing area of circle
cout<<"Area of circle is: "<<(myCircle.getArea())<<endl;
return 0;
}
The answer that completes the blank provided above is the term DIVISIONAL. It is most likely that a divisional structure is being utilized when a media company comprises of a separate and autonomous companies for print journalism, tv, movies and the internet.
Answer:
from collections import Counter
def anagram(dictionary, query):
newList =[]
for element in dictionary:
for item in query:
word = 0
count = 0
for i in [x for x in item]:
if i in element:
count += 1
if count == len(item):
newList.append(item)
ans = list()
for point in Counter(newList).items():
ans.append(point)
print(ans)
mylist = ['jack', 'run', 'contain', 'reserve','hack','mack', 'cantoneese', 'nurse']
setter = ['ack', 'nur', 'can', 'con', 'reeve', 'serve']
anagram(mylist, setter)
Explanation:
The Counter class is used to create a dictionary that counts the number of anagrams in the created list 'newList' and then the counter is looped through to append the items (tuple of key and value pairs) to the 'ans' list which is printed as output.
